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alexira [117]
3 years ago
12

College Calculus - hyperbolic functions (see attachment)

Mathematics
2 answers:
morpeh [17]3 years ago
6 0

Answer:

g(x) = sinh^-1 ( ln(7x^6 +3) / sqrt( 8+cot( x^( 3+x))))

Step-by-step explanation:

Using the fundamental theorem of calculus

Taking the derivative of the integral gives back the function

Since the lower limit is a constant when we take the derivative it is zero

d/dx \int\limits^x_4 {g(t)} \, dt  = g(x)

g(t) = sinh^-1 ( ln(7t^6 +3) / sqrt( 8+cot( t^( 3+t))))

Replacing t with x

g(x) = sinh^-1 ( ln(7x^6 +3) / sqrt( 8+cot( x^( 3+x))))

tatiyna3 years ago
3 0
<h3>Answer: <em>g(x) = sinh^-1 ( ln(7x^6 +3) / sqrt( 8+cot( x^( 3+x))))</em></h3>

Step-by-step explanation:

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In the pulley system shown in this figure, MQ = 30 mm, NP = 10 mm, and QP = 21 mm. Find MN.
ankoles [38]
<h2>Answer:</h2>

\boxed{\overline{MN}=37.96}

<h2>Step-by-step explanation:</h2>

For a better understanding of this problem, see the figure below. Our goal is to find \overline{MN}. Since:

\angle MRS=\angle MQP=90^{\circ} \\ \\ \overline{MQ}=\overline{MR}=30mm

and \overline{MN} is a common side both for ΔMRN and ΔMQN, then by SAS postulate, these two triangles are congruent and:

\overline{RN}=\overline{QN}

By Pythagorean theorem, for triangle NQP:

\overline{QN}=\sqrt{\overline{NP}^2+\overline{QP}^2} \\ \\ \overline{QN}=\sqrt{10^2+21^2} \\ \\ \overline{QN}=\sqrt{541}

Applying Pythagorean theorem again, but for triangle MQN:

\overline{MN}=\sqrt{\overline{MQ}^2+\overline{QN}^2} \\ \\ \overline{MN}=\sqrt{30^2+(\sqrt{541})^2} \\ \\ \boxed{\overline{MN}=37.96}

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A carpenter used 9 1/2 ft of cedar for every 7 2/3 ft of redwood for a construction project. If the carpenter uses 4 3/4 ft of c
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We can make a proportion to represent the woods used. On the top  is cedar, and on the bottom is the redwood. On the left is what was used the first time, on the right is the current problem.

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7\frac{2}{3} =  \frac{3 * 7 + 2}{3} =\frac{23}{3}  

4\frac{3}{4} =  \frac{4 * 4 + 3}{4} =\frac{19}{4}  

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\frac{19/2}{23/3} =\frac{19/4}{R}

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R = (\frac{23}{3} *\frac{19}{4} ) / \frac{19}{2}

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R = \frac{23}{3} *\frac{1}{2} *  \frac{1}{1}

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R = 23 * 1 * 1 / 3 * 2 * 1

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