College Calculus - hyperbolic functions (see attachment)
2 answers:
Answer:
g(x) = sinh^-1 ( ln(7x^6 +3) / sqrt( 8+cot( x^( 3+x))))
Step-by-step explanation:
Using the fundamental theorem of calculus
Taking the derivative of the integral gives back the function
Since the lower limit is a constant when we take the derivative it is zero
d/dx
g(t) = sinh^-1 ( ln(7t^6 +3) / sqrt( 8+cot( t^( 3+t))))
Replacing t with x
g(x) = sinh^-1 ( ln(7x^6 +3) / sqrt( 8+cot( x^( 3+x))))
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So,
The standard form is:
y = mx + b
First, we find "m," the slope. Subtract the y-coordinates from each other. Do likewise with the x-coordinates.
2 - -3 = 5
2 - 0 = 2
Slope = 5/2
Now, we can substitute the second solution into this equation for x and y and solve for "b."
Now we have our complete equation.
The standard form is:
y = mx + b
First, we find "m," the slope. Subtract the y-coordinates from each other. Do likewise with the x-coordinates.
2 - -3 = 5
2 - 0 = 2
Slope = 5/2
Now, we can substitute the second solution into this equation for x and y and solve for "b."
Now we have our complete equation.