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alexira [117]
3 years ago
12

College Calculus - hyperbolic functions (see attachment)

Mathematics
2 answers:
morpeh [17]3 years ago
6 0

Answer:

g(x) = sinh^-1 ( ln(7x^6 +3) / sqrt( 8+cot( x^( 3+x))))

Step-by-step explanation:

Using the fundamental theorem of calculus

Taking the derivative of the integral gives back the function

Since the lower limit is a constant when we take the derivative it is zero

d/dx \int\limits^x_4 {g(t)} \, dt  = g(x)

g(t) = sinh^-1 ( ln(7t^6 +3) / sqrt( 8+cot( t^( 3+t))))

Replacing t with x

g(x) = sinh^-1 ( ln(7x^6 +3) / sqrt( 8+cot( x^( 3+x))))

tatiyna3 years ago
3 0
<h3>Answer: <em>g(x) = sinh^-1 ( ln(7x^6 +3) / sqrt( 8+cot( x^( 3+x))))</em></h3>

Step-by-step explanation:

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