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Inga [223]
2 years ago
9

Determine if each statement must be true could possibly be true or definitely not true explain or show your reasoning

Mathematics
2 answers:
Allisa [31]2 years ago
5 0

Answer:

The sides must be proportionate. This means is not always true that isosceles triangles are similar. Since equilateral triangles always have 3 angles that are 60° degrees.

Any kind of equilateral triangle would be similar

DENIUS [597]2 years ago
4 0

Answer:

Equilateral triangles are always similar, whereas isosceles triangles are not necessarily comparable.

The angles in one triangle must have the same values as the angles in the other triangle for two triangles to be identical. The lengths of the sides must be proportional.

Both may be isosceles, however one may have 30°, 30°120° angles and the other may have 20°, 20° 140° angles.

As a result, isosceles triangles are not necessarily comparable.

Because equilateral triangles always have three angles of 60 degrees apiece, any

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Could someone please help me out? I've tried to solve this but I'm really having some trouble with it. Please try to explain it
guajiro [1.7K]

To find the area of the shaded region you need find the area of the shaded region and subtract the area of the unshaded region.

Area of a rectangle = width x length

A = (x + 10) x (2x + 5)

Next apply FOIL or First Outer Inner Last

A = (x * 2x) (x * 5) (10 * 2x) (10 * 5)

A= 2x2 + 5x + 20x + 50

A= 2x2 +25x +50

 

Area of a square=  sides2

A= (x + 1)2

A= (x+1) (x+1)

Next apply FOIL or First Outer Inner Last

A = (x *x) (1*x) (1*x) (1*1)

A = x2 + 1x + 1x +1

A= x2 + 2x +1

 

A= 2x2 +25x +50 - 2x2 +25x +50

A= 50x + 100





4 0
3 years ago
Verify that P = Ce^t /1 + Ce^t is a one-parameter family of solutions to the differential equation dP dt = P(1 − P).
NemiM [27]

Answer:

See verification below

Step-by-step explanation:

We can differentiate P(t) respect to t with usual rules (quotient, exponential, and sum) and rearrange the result. First, note that

1-P=1-\frac{ce^t}{1+ce^t}=\frac{1+ce^t-ce^t}{1+ce^t}=\frac{1}{1+ce^t}

Now, differentiate to obtain

\frac{dP}{dt}=(\frac{ce^t}{1+ce^t})'=\frac{(ce^t)'(1+ce^t)-(ce^t)(1+ce^t)'}{(1+ce^t)^2}

=\frac{(ce^t)(1+ce^t)-(ce^t)(ce^t)}{(1+ce^t)^2}=\frac{ce^t+ce^{2t}-ce^{2t}}{(1+ce^t)^2}=\frac{ce^t}{(1+ce^t)^2}

To obtain the required form, extract a factor in both the numerator and denominator:

\frac{dP}{dt}=\frac{ce^t}{1+ce^t}\frac{1}{1+ce^t}=P(1-P)

3 0
3 years ago
What fraction of his allowance did he spend on monday 1/6 3/6?
natima [27]
Is this from iready cuz I don’t I’ve had that question before
7 0
3 years ago
Evaluate the expression for k = 17.<br><br> 3k =
Debora [2.8K]
I believe this would be 51
7 0
3 years ago
Add the two expressions.<br><br> −2.4n−3 and −7.8n+2
Sphinxa [80]

Answer:

-10.2n - 1

Step-by-step explanation:

We have two expressions in variable n and we have to add the two expressions.

An important thing to note is that only like terms can be added. i.e. the term with "n" can only be added or subtracted to the term with "n". Similarly a constant can only be added or subtracted to a constant.

(-2.4n-3)+(-7.8n+2)\\=-2.4n-3-7.8n+2\\=-2.4n-7.8n-3+2\\=-10.2n-1

Thus, the two given expressions add up to -10.2n - 1

4 0
2 years ago
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