This is an example of a series in arithmetic progression.
The nth term an can be calculated using the formula:
an = a1 + (n – 1) d
<span>where: a1 = is the 1st term of the series</span>
d = common difference
<span>Calculating for the 1st term:</span>
a1 = 2k + 4 = 2 (1) + 4 = 6
Calculating for the common difference by :
d = a2 – a1
d = 2 (2) + 4 – 6
d = 2
Therefore calculating for an:
an = 6 + (n – 1) 2
an = 6 + 2n -2
an =
2n + 4
Therefore
the answer is B. 2n+4
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