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3 years ago

Is the number given a solution to the equation? c = 2c - 4; 8

Mathematics

1 answer:

Sveta_85 [38]3 years ago

6 0

No i dint think it is 2×8-4=12 and 8 is not equal to 12 :)

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David is filling five 3/4quart bottles with a sports drinks.His measuring cup only holds 1/4 quart. How many times will David ne

vazorg [7]

Answer:

15 times

Step-by-step explanation:

Easy peasy!

So 3/4 is one whole bottle right?

The measuring cup holds only 1/4 while you need 3/4 so you fill it 3 times to fill the cup but remember you have 4 more cups to fill so you multiply 3 and 5 to get 15!!

You multiply 3 because it takes 3 measuring cups to fill a bottle and there’s 5 cups in all

Let me know if I’m wrong

Hope this helped and good luck!

3 0

3 years ago

Please help !! thank you so much!!

Afina-wow [57]

Step-by-step explanation:

we know that:

$tan(x - y) = \frac{tanx - tany}{1 + tanx \times tany}$

using this, we can see that x = 73 and y = 13

using this, tan(x-y) = tan(73-13) = tan(60)

therefore, A = 60

we know that tan(60) = √3

therefore, B = 3

5 0

3 years ago

Which number is the largest? A. 20.999 B. 21.767 C. 21.76 D. 21.80 E. 21.798

Elza [17]

Answer:

21.80

Step-by-step explanation:

3 0

2 years ago

F(x)=x^3+6x^2+x^1/2 and g(x)+x^1/2 . find f(x) divided by g(x)

dolphi86 [110]

To solve this problem you must apply the proccedure shown below:

1. You have that $f(x)=x^{3}+6x^{2}+x^{\frac{1}{2}}$ and $g(x)=x^{\frac{1}{2}}$ , therefore, you must divide must fucntion, as following:

$\frac{f(x)}{g(x)}=\frac{x^{2}+6x^{2}+x^{\frac{1}{2}}}{x^{\frac{1}{2}}}$

2. You must simplify it,by factoring out $x^{\frac{1}{2}}$ , as following:

$\frac{f(x)}{g(x)}=\frac{x^{\frac{1}{2}}( x^{\frac{5}{2}}+6x^{\frac{3}{2}}+1)}{x^{\frac{1}{2}}}$

3. Finally, you obtain that the answer is:

$\frac{f(x)}{g(x)}= x^{ \frac{5}{2} } +6 x^{ \frac{3}{2} } +1$

7 0

3 years ago

Write the expression as a single natural logarithm.3 ln x – 5 ln c

shtirl [24]

The rules are ...
$\Longrightarrow \ln(\frac{a}{b})=\ln(a)-\ln(b)$
$\Longrightarrow \ln(a^{b})=b\ln(a)$

Your expression makes use of both these rules.
$3\ln(x)-5\ln(c)=\ln(x^{3})-\ln(c^{5})=\ln \left( \dfrac{x^{3}}{c^{5}} \right)$

Your single logarithm is ...
$\ln \left( \dfrac{x^{3}}{c^{5}} \right)$

4 0

4 years ago