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nikklg [1K]
3 years ago
13

The sum of the fifth and sixth term of an AP is 30.If the third term is 5.Find the first term.​

Mathematics
1 answer:
dsp733 years ago
3 0

Answer:

The first term is -3.

Step-by-step explanation:

Arithmetic sequence:

In an arithmetic sequence, the difference between two consecutive terms is always the same, and it is called common difference d.

The nth term is given by:

a_n = a_1 + (n-1)d

In which a_1 is the first term.

If we have the mth term instead of the first, we have:

a_n = a_m + (n-m)d

We have the third term, and need the fifth and the sixth:

So we write both the fifth and the sixth in function of the third, then:

a_5 = a_3 + 2d = 5 + 2d

a_6 = a_3 + 3d = 5 + 3d

The sum of the fifth and sixth term of an AP is 30

We use this to find d. So

a_5 + a_6 = 30

5 + 2d + 5 + 3d = 30

5d + 10 = 30

5d = 20

d = \frac{20}{5} = 4

First term:

The third term is:

a_3 = a_1 + 2d

Since a_3 = 5, d = 4

a_1 = a_3 - 2d = 5 - 8 = -3

The first term is -3.

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Mandarinka [93]

Answer:

<h2>x = 3.1</h2>

Step-by-step explanation:

<h3>{10}^{x}  = 1200</h3>

<u>To solve first take logarithm to both sides</u>

That's

<h3>log_{10}(10) ^{x}  =  log_{10}(1200)</h3><h3 /><h3>log_{10}(10)^{x}  = x log_{10}(10)</h3>

But

<h3>log_{10}(10)  = 1</h3>

So we have

x =  log_{10}(1200)

<u>Write 1200 as a number with the factor 100</u>

That's

1200 = 100 × 12

So we have

<h3>x =  log_{10}(100 \times 12)</h3>

<u>Using the rules of logarithms</u>

That's

<h3>log_{a}(x \times y)  =  log_{a}(x)  +  log_{a}(y)</h3>

Rewrite the expression

That's

<h3>x =  log_{10}(100)  +  log_{10}(12)</h3><h3 /><h3>x =  log_{10}(10)^{2}  +  log_{10}(12)</h3><h3>x = 2 log_{10}(10)  +  log_{10}(12)</h3><h3>log_{10}(10)  = 1</h3><h3 /><h3>x = 2 +  log_{10}(12)</h3>

x = 3.079

So we have the final answer as

<h3>x = 3.1 to one decimal place</h3>

Hope this helps you

8 0
3 years ago
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