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3 years ago

Find the GCF. 6m3n and 8mn2

Mathematics

1 answer:

Liono4ka [1.6K]3 years ago

6 0

Answer:

$2mn$

Step-by-step explanation:

$6m^3n,\:8mn^2$

Find the GCD of $6,\:8$ :

$6$

$=2\cdot \:3$

$8$

$=2\cdot \:4$

$=2\cdot \:2\cdot \:2$

So the prime factor common to 6, 8 is:

$2$

So the factor common to $6m^3n,\:8mn^2$ :

$=2mn$

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Divide -2x^3-5x^2+4x+2 by x+2

erik [133]

Answer:

The correct option is C. $-2x^2-x+6, R(-10)$

Explanation:

Given:

Dividend = -2x^3-5x^2+4x+2

Divider =(x+2)

Solution:

Now by using the division method , we will find out the quotient and remainder of the given equation

And the equation will become

$-2x^3-5x^2+4x+2=(x+2)(-2x^2-x+6)-10$

So , We will get the quotient = $-2x^2-x+6$

And Remainder = -10

Hence the Correct option which perfectly satisfy the given equation is C.

4 0

3 years ago

Which of the following is not a property of quadrilaterals? A. There are four sides. B. There are four diagonals. C. There are f

Katarina [22]

A quadrilateral has 4 vertices and the sum of the measures of the interior angles is 360 degrees. There cannot be 4 diagonals in a quadrilateral.

5 0

3 years ago

julia is putting together bag of 45 blocks. if she wants the probability of choosing a red block to be 1/5 how many red blocks j

4vir4ik [10]

Answer:

Step-by-step explanation:

Given that the sample size is 45 blocks

Let number of red blocks in the bag to be x

Then the probability of chosing a red block will be x/45

Given that the probability of choosing a red block is 1/5 then you can form the expression;

x/45 = 1/5 ---------------find the value of x by performing cross multiplication

5x=45*1

5x/5=45/5

x=9

Answer

Julia put 9 red blocks in the bag.

7 0

3 years ago

Question 1 Solve: 25.6 - 5y + 15. 3

QveST [7]

Answer:

40.9 - 5y

Step-by-step explanation:

25.6 - 5y + 15.3

40.9 - 5y ## ^ combine like-terms

8 0

3 years ago

From a group of 8 volunteers, including Andrew and Karen, 4 people are to be selected at random to organize a charity event. Wha

Helga [31]

Answer:

The correct option is D. 2/7

Step-by-step explanation:

Consider the provided information.

There are 8 volunteers including Andrew and Karen, 4 people are to be selected at random to organize a charity event.

We need to determine the probability Andrew will be among the 4 volunteers selected and Karen will not.

We want to select Andrew and 3 others but not Karen in the group.

Thus, the number of ways to select 3 member out of 8-2=6

(We subtract 2 from 8 because Andrew is already selected and we don't want Karen to be selected, so subtract 2 from 8.)

The required probability is:

$\dfrac{^6C_3}{^8C_4}=\dfrac{\frac{6!}{3!3!}}{\frac{8!}{4!4!}}\\\\\\\dfrac{^6C_3}{^8C_4}=\frac{20}{70}\\\\\\\dfrac{^6C_3}{^8C_4}=\dfrac{2}{7}$

Hence, the correct option is D. 2/7

6 0

4 years ago