I need help on C, D, E, F, G, and H. The mean is 27, and the Standard Deviation is 15.01

Can someone help me .

RUDIKE [14]

Answer:

b part is the correct answer

3 0

3 years ago

P = {52, 77, 91, 124,<br> 217)<br> Three members of the set P have a common<br> factor which is

Marrrta [24]

tis always a good idea when factoring to start off with a quick prime factoring.

$\begin{array}{llll} 52&=&2\cdot 2\cdot 13\\\\ 77&=&\boxed{7}\cdot 11\\\\ 91&=&\boxed{7}\cdot 13\\\\ 124&=&2\cdot 2\cdot 31\\\\ 217&=&\boxed{7}\cdot 31 \end{array}$

4 0

2 years ago

A statistics student wants to compare his final exam score to his friend's final exam score from last year; however, the two exa

yarga [219]

Answer:

$z= \frac{85-70}{10}=1.5$

$z= \frac{45-35}{5}=2$

So then the correct answer for this case is:

B) Our student, Z= 1.50; his friend, Z=2.00.

Step-by-step explanation:

Assuming this complete question:

A statistics student wants to compare his final exam score to his friend's final exam score from last year; however, the two exams were scored on different scales. Remembering what he learned about the advantages of Z scores, he asks his friend for the mean and standard deviation of her class on the exam, as well as her final exam score. Here is the information:

Our student: Final exam score = 85; Class: M = 70; SD = 10.

His friend: Final exam score = 45; Class: M = 35; SD = 5.

The Z score for the student and his friend are:

A) Our student, Z= -1.07; his friend, Z= -1.14.

B) Our student, Z= 1.50; his friend, Z=2.00.

C) Our student, Z= 1.07; his friend, Z= -1.14.

D) Our student, Z= 1.07; his friend, Z= 1.50

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution

Let X the random variable that represent the scores for our student, and for this case we know that:

$E(X)= \mu =70, SD_X=\sigma=10$