You can use this formula <span>P(AorB) = P(A) + P(B) - P(AandB)
Given:
35 LG (14 F & 21 M)
44 SB (28 F & 16 M)
Req:
- the probability that it is a female (F) or a sky blue (SB)
Sol:
</span>P(F or SB) = P(F) + P(SB) - P(F and SB)
= [(14 F + 28 F)/(35 + 44)] + [(44 SB)/(35 + 44)] - [(28 F)/(35 + 44)]
= 53.16 + 55.70 - 35.44
= 73.42%
You have to deduct 28 female parakeets from 44 sky blue parakeets because the 28 parakeets are already accounted for in the female parakeets. You can also think of how many ways you can choose a female parakeet and a sky blue parakeet. Add all female parakeets (14 + 28) = 42. Sky blue parakeet equaled to 44. Minus the 28 female parakeets included in the sky blue parakeet to avoid double counting. 42 + 44 - 28 = 58 divided by 79 (35 + 44) total parakeets = 73.42%
Answer x = 24 + 3x
Step-by-step explanation:
(Y/4) +3 = 7
Subtract 3 from both sides:
Y/4 = 4
Multiply both sides by 4
Y = 16
Answer:
(2x - 7)³ ≠ (2x)³- 7³
Step-by-step explanation:
(2x - 7)³= (2x)³- 7³
Use pascal's triangle to expand left side. Simplify all else.
(2x)³ + 3(2x)²(-7)¹ + 3(2x)¹(-7)² + (-7)³ = 8x³- 343
8x³ + 3(4x²)(-7) + 3(2x)(49) + (-7)³ = 8x³- 343
8x³ - 84x² + 294x - 343 = 8x³- 343
LS ≠ RS
A deck of cards contains red cards numbered 1,2,3,4,5, blue cards numbered 1,2 and green cards numbered 1,2,3,4,5,6. If a single
tekilochka [14]
Answer:
the probability is 38,46%
Step-by-step explanation:
If all decks are put together and shuffled , then card is picked at random regardless of the number, then the probability that the card is red is
probability = number of red cards / total number of cards = 5/(5+2+6) = 5/13=0.3846= 38,46%
