What is the answer??)

Rafael can choose plan a or Plan B for his long-distance charges. For each plan, cost (in dollars) depends on minutes used (Per

PilotLPTM [1.2K]

Answer:

a. Plan B; $4

b. 160 mins; Plan B

Step-by-step explanation:

a. Cost of Plan A for 80 minutes:

Find 80 on the x axis, and trave it up to to intercept the blue line (for Plan A). Check the y axis to see the value of y at this point. Thus:

f(80) = 8

This means Plan A will cost $8 for Rafael to 80 mins of long distance call per month.

Also, find the cost per month for 80 mins for Plan B. Use the same procedure as used in finding cost for plan A.

Plan B will cost $12.

Therefore, Plan B cost more.

Plan B cost $4 more than Plan A ($12 - $8 = $4)

b. Number of minutes that the two will cost the same is the number of minutes at the point where the two lines intercept = 160 minutes.

At 160 minutes, they both cost $16

The plan that will cost less if the time spent exceeds 160 minutes is Plan B.

4 0

3 years ago

Which statement is true?

marshall27 [118]

Answer:

B, the second answer choice

Step-by-step explanation:

Hope this helped! Please mark me as brainliest if you can!

4 0

3 years ago

A contractor is given a scale drawing of a rectangular patio. The scale from the patio to the drawing is 4ft to 1in. What is the

AnnyKZ [126]

Answer:

170 ft²

Step-by-step explanation:

Given:

Patio drawing of 4.25 in by 2.5 in

Scale of Patio to its drawing = 4ft to 1 in

Requires:

Area of actual Patio

SOLUTION:

Area of actual Patio = area of a rectangle = length × width

Given a scale drawing of 4ft to 1 in, therefore:

Length of actual Patio = 4.25 × 4 = 17 ft

Width of actual Patio = 2.5 × 4 = 10 ft

Therefore:

Area of actual Patio = 17 ft × 10 ft = 170 ft²

5 0

3 years ago

mark is drawing a map of his favorite park. the park is 3 miles long and 1.5 miles wide. the map scale is 1 inch = .25 miles. ho

Brilliant_brown [7]

Answer: 6 inches

Step-by-step explanation:

1.5 miles wide * 1 inch / 0.25 miles = 6 inches :D

7 0

3 years ago

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An airplane climbs 100 feet during the first second after takeoff. In each succeeding second it climbs 100 feet more than it cli

tigry1 [53]

Answer:

15 seconds.

Step-by-step explanation:

∵ The distance covered by plane in first second = 100 ft,

Also, in each succeeding second it climbs 100 feet more than it climbed during the previous second,

So, distance covered in second second = 200,

In third second = 300,

In fourth second = 400,

............, so on....

Thus, the total distance covered by plane in n seconds = 100 + 200 + 300 +400......... upto n seconds

$=\frac{n}{2}(2\times 100 + (n-1)100)$ ( Sum of AP )

$=\frac{n}{2}(200+100n-100)$

$=\frac{n}{2}(100+100n)$

$=50n+50n^2$

Suppose the distance covered in n seconds is 12,000 feet,

$\implies 50n+50n^2=12000$

$n+n^2=240$

$n^2+n-240=0$

$n^2+16n-15n-240=0$

$n(n+16)-15(n+16)=0$

$(n-15)(n+16)=0$

$\implies n=15\text{ or }n=-16$

∵ n can not be negative,

Hence, after 15 seconds the plane will reach an altitude of 12,000 feet above its takeoff height.

6 0

3 years ago

Read 2 more answers