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Leviafan [203]
3 years ago
13

Can someone help me please!? Can you show the work as well! :)

Mathematics
1 answer:
vovangra [49]3 years ago
4 0
Ok done. Thank to me :>

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Jessie says to round 763 400 to the nearest ten thousand he will round to 770 000 is he right ?
skad [1K]
No because it's closer to 760,000
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The graph of y = x³ + x² - 6x is shown. a) Estimate the x-coordinates of the turning points of the graph. X= Note: Please use a
KIM [24]

Answer:

Below.

Step-by-step explanation:

(a). The x estimations of the turning points are -1.8 and 1.1, according to the graph.

(b). Where the graph crosses the x axis are the solutions. x = -3, 0, and 2 are the values.

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2 years ago
Find the radius of a circle with a circumference of 69.1 yd
Arte-miy333 [17]

34.55 gcgbycfgycbnfuymiklbdxrdytjmu

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3 years ago
What is the current yield on a 3 year bond with 10% annual coupons, a par value of 100, and a current price of 107.87?
hichkok12 [17]

The current yield of the bond is 9.27%.

What is current yield?

Current yield is the bond rate of return computed as the annual coupon divided by the current price of the bond

The annual coupon is the coupon rate of 10% multiplied by the bond's par value of 100

annual coupon=10%*100

annual coupon=10

current bond price=107.87

current yield=annual coupon/current bond price

current yield=10/107.87

current yield=9.27%

Find more on current yield on:brainly.com/question/12909555

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5 0
2 years ago
Of 375 randomly selected students, 30 said that they planned to work in a rural community. Find 95% confidence interval for the
Artemon [7]

Answer:

The 95% confidence interval for the true proportion of all medical students who plan to work in a rural community is (0.0525, 0.1075).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 375, \pi = \frac{30}{375} = 0.08

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.08 - 1.96\sqrt{\frac{0.08*0.92}{375}} = 0.0525

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.08 + 1.96\sqrt{\frac{0.08*0.92}{375}} = 0.1075

The 95% confidence interval for the true proportion of all medical students who plan to work in a rural community is (0.0525, 0.1075).

4 0
3 years ago
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