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loris [4]
3 years ago
8

Which statement is true?

Mathematics
1 answer:
marshall27 [118]3 years ago
4 0

Answer:

B, the second answer choice

Step-by-step explanation:

Hope this helped! Please mark me as brainliest if you can!

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Is 5/6 greater than 1/2
Alinara [238K]
Yes it is. We know this cause 1 is smaller than 5 and 6 is bigger than 2. 

Hope This Helps!





7 0
3 years ago
A bookcase has 6 shelves.
Bezzdna [24]

Answer:

21 books

Step-by-step explanation:

130-4=x

x/6= answer

6 0
3 years ago
Read 2 more answers
Let A be a 3×3 matrix and suppose we know that −2a1+3a2−5a3=0 where a1,a2 and a3 are the columns of A. Write a non-trivial solut
belka [17]

Answer:

One of the obvious non-trivial solutions is  (x_1, x_2, x_3)=(-2, 3, -5).

Step-by-step explanation:

Suppose the matrix A is as follows:

A=\left[\begin{array}{ccc}a_{11}&a_{12}&a_{13}\\a_{21}&a_{22}&3_{23}\\a_{31}&a_{32}&a_{33}\end{array}\right]

The observed system Ax=0 after multiplying looks like this

Ax=0 \iff \left[\begin{array}{ccc}a_{11}&a_{12}&a_{13}\\a_{21}&a_{22}&a_{23}\\a_{31}&a_{32}&a_{33}\end{array}\right] \cdot \left[\begin{array}{ccc}x_1\\x_2\\x_3\end{array}\right] =0 \iff \\ \\a_{11}x_1+a_{12}x_2+a_{13}x_3=0\\a_{21}x_1+a_{22}x_2+a_{23}x_3=0\\a_{31}x_1+a_{32}x_2+a_{33}x_3=0\\\\

Since we now that -2A_1+3A_2-5A_3=0, where A_i\ ,\  i=1, 2, 3 are the columns of the matrix A, we actually know this:

-2\cdot \left[\begin{array}{ccc}a_{11}\\a_{21}\\a_{31}\end{array}\right] +3\cdot \left[\begin{array}{ccc}a_{12}\\a_{22}\\a_{32}\end{array}\right] -5\cdot \left[\begin{array}{ccc}a_{13}\\a_{23}\\a_{33}\end{array}\right] =\left[\begin{array}{ccc}0\\0\\0\end{array}\right]

Once we multiply and sum up these 3 by 1 matrices, we get that these equations hold:

-2a_{11}+3a_{12}-5a_{13}=0\\-2a_{21}+3a_{22}-5a_{23}=0\\-2a_{31}+3a_{32}-5a_{33}=0

This actually means that the solution to the previously observed system of equations (or equivalently, our system Ax=0) has a non-trivial solution (x_1, x_2, x_3)=(-2, 3, -5).

8 0
3 years ago
What is the quotient of (3+I)(3-I)/-(2+2i)^2
Sidana [21]

Answer:

E. -5i/4

Step-by-step explanation:

\frac{9 + 3i - 3i -i^{2}}{-4 -8i -4i^{2} } =\frac{9-(-1)}{-4-8i-4(-1)} =\frac{10}{-8i} =\frac{-5}{4i} =\frac{-5i}{4}

7 0
3 years ago
Equation of a horizontal line that contains the point (9,8)
kati45 [8]

The equation could be y=8, because the line will pass through any coordinate with a Y value of 8

3 0
3 years ago
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