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faltersainse [42]
2 years ago
13

Write an equation in slope-intercept form of the line that passes through (−2, 5) and (−4, −5).

Mathematics
1 answer:
Trava [24]2 years ago
7 0

y  =  − 1 /8x - 19/4

i think

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Answer:

what does d equal?

Step-by-step explanation:

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104 km= m? metric conversions104 km= m? metric conversions Follow 8 answers 8 Report Abuse Are you sure you want to delete this
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3 years ago
Find the nth term of 67,56,45,34
kvv77 [185]

Answer:

  an = 67 -11(n -1)

Step-by-step explanation:

The terms of your arithmetic sequence have a common difference of -11. The first term is 67.

These values can be used in the generic formula for the n-th term:

  an = a1 +d(n -1) . . . . . . first term a1, common difference d

  an = 67 -11(n -1) . . . . . formula for the n-th term

7 0
2 years ago
Statistics question about random probability Cheese pastureized or Raw MilkA cheese can be classified as either raw-milk or past
blsea [12.9K]

Answer:

(a) Two cheeses are chosen at random. the probability that both cheeses are pasteurized is Pr(PP) = 0.82 x 0.82 = 0.6724 to 4 decimal places)

(b) Four cheeses are chosen at random. The probability that all four cheeses are pasteurized is Pr(PPPP) = 0.82 x 0.82 x 0.82 x 0.82 = 0.4521 to 4 decimal places

(c) What is the probability that at least one of four randomly selected cheeses is raw-milk is Pr(RPPP) Or Pr(RRPP) Or Pr(RRRP) Or Pr(RRRR)

= 0.1269 to 4 decimal places

It would not be unusual that at least one of four randomly selected cheeses is raw-milk, because the probability have a value between 0 and 1

Step-by-step explanation:

If is given that 80% of the cheese is classified as pasteurized.

It then implies that 20% of the cheese is classified as Raw-milk

Probability of pasteurized cheese is 0.82(Denoted by Pr(P))

Probability of raw-milk cheese is 0.18(Denoted as Pr(R))

(a) Two cheeses are chosen at random. the probability that both cheeses are pasteurized is Pr(PP) = 0.82 x 0.82 = 0.6724 to 4 decimal places)

(b) Four cheeses are chosen at random. The probability that all four cheeses are pasteurized is Pr(PPPP) = 0.82 x 0.82 x 0.82 x 0.82 = 0.4521 to 4 decimal places

(c) What is the probability that at least one of four randomly selected cheeses is raw-milk is Pr(RPPP) + Pr(RRPP) + Pr(RRRP) + Pr(RRRR)

(0.18 x 0.82 x 0.82 x 0.82) + (0.18 x 0.18 x 0.82 x 0.82) + (0.18 x 0.18 x 0.18 x 0.82) + (0.18 x 0.18 x 0.18 x 0.18) = 0.1269 to 4 decimal places

3 0
3 years ago
The price of 10 citrons and 7 fragrant wood apples is 55 units. The price of 7 citrons and 10 fragrant wood apples is 64 units.
a_sh-v [17]

Price of one citron = 5 units

Price of one fragrant = 5/7 units = 0.71 units

Further explanation:

Let x be the price of one citron and

y be the price of one fragrant

Then according to given statement

10x+7y = 55         Eqn 1

7x+10y = 64          Eqn 2

Multiplying equation 1 by 7

7(10x+7y) = 7(55)\\70x+49y=385

This will be equation 3.

Multiplying equation 2 by 10

10(7x+10y) = 10(64)\\70x+100y=640

This will be equation 4.

Subtracting equation 3 from equation 4

70x+100y - (70x+49y) = 640-385\\70x+100y-70y-49y = 255\\51y = 255\\\frac{51x}{51} = \frac{255}{51}\\x = 5\\Putting\ x=5\ in\ equation\ 1\\10(5)+7y = 55\\50+7y = 55\\7y = 55-50\\7y = 5\\\frac{7y}{7} =\frac{5}{7}

So,

Price of one citron = 5 units

Price of one fragrant = 5/7 units = 0.71 units

Keywords: Linear Equations, Solving system of linear equations

Learn more about linear equations at:

  • brainly.com/question/13168205
  • brainly.com/question/1357167
  • brainly.com/question/1542444

#LearnwithBrainly

5 0
2 years ago
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