Answer:
NO
Step-by-step explanation:
Note :
Consider a triangle with sides‘s length a , b and c
triangle inequalities state that we must have c - a < b < c + a
now , is the third side always the longest ?
the answer is NO: (let’s take a counter example )
in a triangle with 2 sides‘s length 3 , 4
the third side could measure 2
because 4-3 < 2 < 4+3
Answer:
and 
Step-by-step explanation:
Given
Bisector: CD
of Line AB
Required
Apply Pythagoras Theorem
From the question, CD bisects AB and it bisects it at D.
The relationship between AB and CD is given by the attachment
Considering ACD
From the attachment, we have that:
By Pythagoras Theorem, we have
Considering CBD
From the attachment, we have that:
By Pythagoras Theorem, we have:
The answer is 9/42. might be wrong I'm rusty on this.
I’m sorry I can’t help ypu
Answer:
H.A.=4
Step-by-step explanation:
If the bottom equation is factored, you get (x+1)(x-4)
If the V.A. is -1 ( gotten by putting [x+1] equal to zero I'm guessing) then the H.A. can be gotten by putting (x-4) equal to zero.
Also, I graphed it.
