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Flura [38]
3 years ago
7

11:59 is the deadline please give me the correct answer​

Mathematics
2 answers:
olasank [31]3 years ago
8 0

Answer:

6 - 8x = 5x - 10x + 15 \\10x-8x-5x=15-6\\  - 3x = 9 \\ x =  \frac{9}{ - 3}  \\ x =  - 3

<h2>-3 is the right answer.</h2>
HACTEHA [7]3 years ago
7 0

Answer:-3

the right answer  did ths on paper

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What is 2.53 rounded to the nearest whole number
ella [17]

Answer:

3.

Step-by-step explanation:

4 0
3 years ago
What is the best way to solve this
Komok [63]
Make 2 equations one for the price and one for quantity.  so first set x = AA and y= AAA. for price 37= 1x+.75y. now for the quantity we have x+y=42. Now we can solve by subtracting the equation for price from the equation for quantity and we get .25y =5. solving this we get y= 20. Now we plug that value back in and solve for x. 22 double A's and 20 triple A's.
6 0
3 years ago
Two competitive neighbours build rectangular pools that cover the same area but are different shapes. Pool A has a width of (x +
GenaCL600 [577]

<u>Answer: </u>

a)Dimensions of pool A are length = 6.667m and width = 3.667 m and dimension of pool B are length = 7.333m and width = 3.333m.

b) Area of pool A is equal to area of pool B equal to 24.44 meters.

<u> Solution: </u>

Let’s first calculate area of pool A .

Given that width of the pool A = (x+3)  

Length of the pool A is 3 meter longer than its width.

So length of pool A = (x+3) + 3 =(x + 6)

Area of rectangle = length x width

So area of pool A =(x+6) (x+3)        ------(1)

Let’s calculate area of pool B

Given that length of pool B is double of width of pool A.

So length of pool B = 2(x+3) =(2x + 6) m

Width of pool B is 4 meter shorter than its length,

So width of pool B = (2x +6 ) – 4 = 2x + 2

Area of rectangle = length x width

So area of pool B =(2x+6)(2x+2)        ------(2)

Since area of pool A is equal to area of pool B, so from equation (1) and (2)

(x+6) (x+3) =(2x+6) (2x+2)    

On solving above equation for x    

(x+6) (x+3) =2(x+3) (2x+2)  

x+6 = 4x + 4    

x-4x = 4 – 6

x = \frac{2}{3}

Dimension of pool A

Length = x+6 = (\frac{2}{3}) +6 = 6.667m

Width = x +3 = (\frac{2}{3}) +3 = 3.667m

Dimension of pool B

Length = 2x +6 = 2(\frac{2}{3}) + 6 = \frac{22}{3} = 7.333m

Width = 2x + 2 = 2(\frac{2}{3}) + 2 = \frac{10}{3} = 3.333m

Verifying the area:

Area of pool A = (\frac{20}{3}) x (\frac{11}{3}) = \frac{220}{9} = 24.44 meter

Area of pool B = (\frac{22}{3}) x (\frac{10}{3}) = \frac{220}{9} = 24.44 meter

Summarizing the results:

(a)Dimensions of pool A are length = 6.667m and width = 3.667 m and dimension of pool B are length = 7.333m and width = 3.333m.

(b)Area of pool A is equal to Area of pool B equal to 24.44 meters.

5 0
4 years ago
PLEASE I NEED HELP NOW!!! IF CORRECT I WILL GIVE BRAINLIEST!!
Ira Lisetskai [31]

Answer:

- 4 4/5 *C

Step-by-step explanation:

12:00-6:00 is 6hrs

7/10*6 = 42/10 = 4 1/5

1 - 4 1/5 = - 4 4/5

4 0
3 years ago
(x−3)÷9=11<br> help idk how to do this
Bess [88]

Answer:

102

Step-by-step explanation:

papa math will help you

x−3

9

=11

Step 1: Multiply both sides by 9.

x−3

9

=11

(

x−3

9

)*(9)=(11)*(9)

x−3=99

Step 2: Add 3 to both sides.

x−3+3=99+3

x=102

Answer:

x=102

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https://www.mathpapa.com/algebra-calculator.html?q=(x%E2%88%923)%5Cdiv9%3D11

x−3

9

=11

Step 1: Multiply both sides by 9.

x−3

9

=11

(

x−3

9

)*(9)=(11)*(9)

x−3=99

Step 2: Add 3 to both sides.

x−3+3=99+3

x=102

Answer:

x=102

Close Ad

Back to Algebra Calculator »

Share this page

Share URL:

https://www.mathpapa.com/algebra-calculator.html?q=(x%E2%88%923)%5Cdiv9%3D11

x−3

9

=11

Step 1: Multiply both sides by 9.

x−3

9

=11

(

x−3

9

)*(9)=(11)*(9)

x−3=99

Step 2: Add 3 to both sides.

x−3+3=99+3

x=102

Answer:

x=102

Close Ad

Back to Algebra Calculator »

Share this page

Share URL:

https://www.mathpapa.com/algebra-calculator.html?q=(x%E2%88%923)%5Cdiv9%3D11

6 0
3 years ago
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