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3 years ago

11:59 is the deadline please give me the correct answer

Mathematics

2 answers:

olasank [31]3 years ago

8 0

Answer:

$6 - 8x = 5x - 10x + 15 \\10x-8x-5x=15-6\\ - 3x = 9 \\ x = \frac{9}{ - 3} \\ x = - 3$

<h2>-3 is the right answer.</h2>

HACTEHA [7]3 years ago

7 0

Answer:-3

the right answer did ths on paper

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Answer:

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Step-by-step explanation:

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3 years ago

What two numbers multiple to -3468 and adds to 24

Alex777 [14]

Answer:

72.1 and -48.1

Step-by-step explanation:

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3 years ago

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Shkiper50 [21]

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2 years ago

Find a a pair of numbers of both 4y-4x=48 and y= x-11

stich3 [128]

Answer:

There is no solution because the slopes of the line are the same.

Step-by-step explanation:

4y - 4x = 48

+ 4x + 4x Add 4x to both sides

4y = 4x + 48 Divide both sides by 4

y = x + 12

Now set both equations equal to each other since they equal y

x + 12 = x - 11

-x - x Subtract x from both sides

12 ≠ -11 No Solution

If this answer is correct, please make me Brainliest!

4 0

2 years ago

Let’s pretend that we want to give our employees in total a28% raise in the next two years, but we want to spread out aconsisten

Roman55 [17]

Solution

- The solution steps are given below:

$\begin{gathered} \text{ Let the original amount be X} \\ \\ \text{ If we want a 28\% raise over the next two years, then it means that the amount will be:} \\ X+\frac{28}{100}X=1.28X \\ \\ \text{ If we want to give them a consistent raise each year, we can compute the scenario as follows:} \\ \text{ Let the percentage be }y \\ \\ X+y\%\text{ of }X=\text{ Salary after first year} \\ \\ (X+y\%\text{ of }X)+y\%\text{ of }(X+y\%\text{ of }X)\text{ = Salary after second year.} \\ \\ \text{ But we already know that the salary after second year is }1.28X \\ \text{ Thus, we can say:} \\ (X+y\%\text{ of }X)+y\%\text{ of }(X+y\%\text{ of }X)=1.28X \\ \\ \text{ Simplifying, we have:} \\ X+\frac{yX}{100}+\frac{y}{100}(X+\frac{yX}{100})=1.28X \\ \\ \text{ Divide through by }X \\ 1+\frac{y}{100}+\frac{y}{100}(1+\frac{y}{100})=1.28 \\ \\ \text{ Subtract 1 from both sides and expand the brackets} \\ \frac{y}{100}+\frac{y}{100}+(\frac{y}{100})^2=1.28-1=0.28 \\ \\ \frac{2y}{100}+(\frac{y}{100})^2=0.28 \\ \\ \text{ Multiply both sides by }100^2 \\ 200y+y^2=2800 \\ \\ \text{ Rewrite, we have:} \\ y^2+200y-2800=0 \\ \\ Solving\text{ the equation using the Quadratic formula, we have that:} \\ y=\frac{-200\pm\sqrt{200^2-4(-2800)}(1)}{2(1)} \\ \\ y=-213.137\text{ or }13.137 \\ \\ \text{ Since the change in salary is an increase, thus, the rate }y\text{ has to be positive.} \\ \text{ Thus, } \\ y=13.137\approx13.14\% \\ \\ \end{gathered}$

Final Answer

y = 13.14%

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5 0

8 months ago

11:59 is the deadline please give me the correct answer​

11:59 is the deadline please give me the correct answer