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Yuki888 [10]
3 years ago
12

Plz help ASAP!!!! PLZ

Mathematics
1 answer:
AnnyKZ [126]3 years ago
3 0
To find a missing side of a right triangle use the Pythagorean theorem
A2+b2=c2
C is the hypotenuse (long side)
Plug into the equation
11^2+b2=12^2
121+b2=144
So subtract 144-121 to get the missing side you get 23
Take the square root
It will be 4.7
If they want it rounded
X=5
If I had any mistakes in my answer I am sorry but everything should be correct
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Which expression is equivalent to
taurus [48]

Answer:

d

Step-by-step explanation:

7 0
3 years ago
Plese i need help on this one !!!!!!!
patriot [66]

Answer:

I got 32.

Step-by-step explanation:

I used the Pythagorean theorem to find the lengths of the width and length. The length between (-1, 4) and (3, 3) was approximately 4 in. The distance between (-1, 4) and (-3, -4) was approximately 8 in. I then used those numbers to find the perimeter ((2*4)+(2*8))

8 0
3 years ago
Read 3 more answers
Please show me how u got theses Answer
musickatia [10]

Answer:

7 x 7 x 7= 49 x 7= 343

3 x 3 x 3 x 3= 9 x 3 x 3= 27 x 3= 81

3 0
2 years ago
Can someone give me an example on a Riemann Sum and like how to work through it ? I want to learn but I don’t understand it when
Georgia [21]

Explanation:

A Riemann Sum is the sum of areas under a curve. It approximates an integral. There are various ways the area under a curve can be approximated, and the different ways give rise to different descriptions of the sum.

A Riemann Sum is often specified in terms of the overall interval of "integration," the number of divisions of that interval to use, and the method of combining function values.

<u>Example Problem</u>

For the example attached, we are finding the area under the sine curve on the interval [1, 4] using 6 subintervals. We are using a rectangle whose height matches the function at the left side of the rectangle. We say this is a <em>left sum</em>.

When rectangles are used, other choices often seen are <em>right sum</em>, or <em>midpoint sum</em> (where the midpoint of the rectangle matches the function value at that point).

Each term of the sum is the area of the rectangle. That is the product of the rectangle's height and its width. We have chosen the width of the rectangle (the "subinterval") to be 1/6 of the width of the interval [1, 4], so each rectangle is (4-1)/6 = 1/2 unit wide.

The height of each rectangle is the function value at its left edge. In the example, we have defined the function x₁(j) to give us the x-value at the left edge of subinterval j. Then the height of the rectangle is f(x₁(j)).

We have factored the rectangle width out of the sum, so our sum is simply the heights of the left edges of the 6 subintervals. Multiplying that sum by the subinterval width gives our left sum r₁. (It is not a very good approximation of the integral.)

The second and third attachments show a <em>right sum</em> (r₂) and a <em>midpoint sum</em> (r₃). The latter is the best of these approximations.

_____

<u>Other Rules</u>

Described above and shown in the graphics are the use of <em>rectangles</em> for elements of the summation. Another choice is the use of <em>trapezoids</em>. For this, the corners of the trapezoid match the function value on both the left and right edges of the subinterval.

Suppose the n subinterval boundaries are at x0, x1, x2, ..., xn, so that the function values at those boundaries are f(x0), f(x1), f(x2), ..., f(xn). Using trapezoids, the area of the first trapezoid would be ...

  a1 = (f(x0) +f(x1))/2·∆x . . . . where ∆x is the subinterval width

  a2 = (f(x1) +f(x2))/2·∆x

We can see that in computing these two terms, we have evaluated f(x1) twice. We also see that f(x1)/2 contributes twice to the overall sum.

If we collapse the sum a1+a2+...+an, we find it is ...

  ∆x·(f(x0)/2 + f(x1) +f(x2) + ... +f(x_n-1) + f(xn)/2)

That is, each function value except the first and last contributes fully to the sum. When we compute the sum this way, we say we are using the <em>trapezoidal rule</em>.

If the function values are used to create an <em>approximating parabola</em>, a different formula emerges. That formula is called <em>Simpson's rule</em>. That rule has different weights for alternate function values and for the end values. The formulas are readily available elsewhere, and are beyond the scope of this answer.

_____

<em>Comment on mechanics</em>

As you can tell from the attachments, it is convenient to let a graphing calculator or spreadsheet compute the sum. If you need to see the interval boundaries and the function values, a spreadsheet may be preferred.

8 0
3 years ago
A company sells fruit cups in packs of 4. The packs currently weigh 20 oz. The company plans to reduce the weight of each cup by
skad [1K]

Answer:

4 ( 5 - n )

Step-by-step explanation:

The expression:

20 – 4n

Task:  Rewrite the expression for the new weight as a product of two factors.

To do this we simply have to find the highest common factor (HCF) between 20 and 4n

20 = 4 * 5

4n = 4 * n

The HCF = 4

Expressing as a product of two factors;

4 ( 5 - n )

6 0
2 years ago
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