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statuscvo [17]
3 years ago
10

Which in quality provides X the number of miles he could afford to drive if he were to rent a car from the company

Mathematics
1 answer:
Rudiy273 years ago
7 0

C would be the correct answer

 the 20 dollar fee plus 25 cents times miles needs to be less tha or equal to the $60 he has to spend.

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What's the area of the square?​
mart [117]
Your answer is D. 25.25
8 0
2 years ago
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The inverse variation equation shows the relationship between wavelength in meters, x, and frequency, y
Cerrena [4.2K]

We have been given that the inverse variation y=\frac{3\times 10^8}{x} shows the relationship between wavelength in meters, x, and frequency, y. We are asked to find the wavelength for radio waves with frequency 3\times 10^9.

To find the required wavelength, we substitute y=3\times 10^9 in our given equation and solve for x as:

3\times 10^9=\frac{3\times 10^8}{x}

x=\frac{3\times 10^8}{3\times 10^9}

We can see that both numerator and denominator has 3, so we can cancel it out.

x=\frac{1\times 10^8}{1\times 10^9}

Using quotient rule of exponents \frac{a^m}{a^n}=a^{m-n}, we will get:

x=1\times 10^{8-9}

x=1\times 10^{-1}

Therefore, the wavelength for radio waves would be 1\times 10^{-1} meters and option B is the correct choice.

3 0
3 years ago
Read 2 more answers
Please determine whether the set S = x^2 + 3x + 1, 2x^2 + x - 1, 4.c is a basis for P2. Please explain and show all work. It is
ohaa [14]

The vectors in S form a basis of P_2 if they are mutually linearly independent and span P_2.

To check for independence, we can compute the Wronskian determinant:

\begin{vmatrix}x^2+3x+1&2x^2+x-1&4\\2x+3&4x+1&0\\2&4&0\end{vmatrix}=4\begin{vmatrix}2x+3&4x+1\\2&4\end{vmatrix}=40\neq0

The determinant is non-zero, so the vectors are indeed independent.

To check if they span P_2, you need to show that any vector in P_2 can be expressed as a linear combination of the vectors in S. We can write an arbitrary vector in P_2 as

p=ax^2+bx+c

Then we need to show that there is always some choice of scalars k_1,k_2,k_3 such that

k_1(x^2+3x+1)+k_2(2x^2+x-1)+k_34=p

This is equivalent to solving

(k_1+2k_2)x^2+(3k_1+k_2)x+(k_1-k_2+4k_3)=ax^2+bx+c

or the system (in matrix form)

\begin{bmatrix}1&1&0\\3&1&0\\1&-1&4\end{bmatrix}\begin{bmatrix}k_1\\k_2\\k_3\end{bmatrix}=\begin{bmatrix}a\\b\\c\end{bmatrix}

This has a solution if the coefficient matrix on the left is invertible. It is, because

\begin{vmatrix}1&1&0\\3&1&0\\1&-1&4\end{vmatrix}=4\begin{vmatrix}1&2\\3&1\end{vmatrix}=-20\neq0

(that is, the coefficient matrix is not singular, so an inverse exists)

Compute the inverse any way you like; you should get

\begin{bmatrix}1&1&0\\3&1&0\\1&-1&4\end{bmatrix}^{-1}=-\dfrac1{20}\begin{bmatrix}4&-8&0\\-12&4&0\\-4&3&-5\end{bmatrix}

Then

\begin{bmatrix}k_1\\k_2\\k_3\end{bmatrix}=\begin{bmatrix}1&1&0\\3&1&0\\1&-1&4\end{bmatrix}^{-1}\begin{bmatrix}a\\b\\c\end{bmatrix}

\implies k_1=\dfrac{2b-a}5,k_2=\dfrac{3a-b}5,k_3=\dfrac{4a-3b+5c}{20}

A solution exists for any choice of a,b,c, so the vectors in S indeed span P_2.

The vectors in S are independent and span P_2, so S forms a basis of P_2.

5 0
2 years ago
Which set of angles are complementary
Deffense [45]

Answer:

A. <ECF and <BCF

Step-by-step explanation:

Complementary angles are angles that add up to give 90°

m<BCE = m<BCA = 90° (right angles)

m<ECF + m<BCF = m<BCA

m<ECF + m<BCF = 90° (Substitution)

Therefore, <ECF and <BCF are complementary angles.

6 0
2 years ago
Simplify 12√18-6√20-3√50-8√45
Alex_Xolod [135]

12√18-6√20-3√50-8√45

<em>*Break each radical up into the product of a radical of a perfect square and a second radical*</em>

12(√9*√2)-6(√4*√5)-3(√25*√2)-8(√9*√5)

<em>*Simplify the radicals*</em>

12(3√2)-6(2√5)-3(5√2)-8(3√5)

<em>*Distribute*</em>

36√2-12√5-15√2-24√5

<em>*Combine like terms</em>*

21√2-36√5

Hope this helps!!

3 0
2 years ago
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