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Luden [163]
3 years ago
9

a popular weekly magazine asserts that fewer than 40% of households in the united states have changed their lifestyles because o

f escalating gas prices. a recent survey of 180 households finds that 67 households have made lifestyle changes due to escalating gas prices.the standard error of p(bar) is:the value of the test statistic is:the pvalue is:at a=0.10 and using the p-valuein light of your conclusion, what test error may happen?
Mathematics
1 answer:
kiruha [24]3 years ago
8 0

Answer: The null hypothesis is not rejected.

Step-by-step explanation:

Since we have given that

n = 180

x = 67

So, \hat{p}=\dfrac{x}{n}=\dfrac{67}{180}=0.372

Hypothesis :

H_0:\hat{p}\geq 0.4\\\\H_1:\hat{p}

So, test statistic value would be

z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}\\\\z=\dfrac{0.372-0.4}{\sqrt{\dfrac{0.4\times 0.6}{180}}}\\\\z=\dfrac{-0.027}{0.03645}\\\\z=-0.741

At 0.01 level of significance, z = -1.28

So, -1.28<-0.741

So, we will not reject the null hypothesis as p - value = 0.2234.

Hence, the null hypothesis is not rejected.

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A baseball player hits a ball toward the outfield. The height h of the ball in feet is modeled by h(t) = -16t2 + 22t + 3, where
Roman55 [17]
h(t)=-16t^2+22t+3\\(0)=-(8t+1)(2t-3)\\8t+1=0:2t-3=0\\8t=-1:2t=3\\t=\frac{-1}{8}:t=\frac{3}{2}

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4 0
3 years ago
A tech company bought a number of computers for its employees: 66 costing \$1600$1600 each, 44 costing \$1200$1200 each, and yy
daser333 [38]

Answer:

5

Step-by-step explanation:

A tech company bought a number of computers for its employees: 6 costing $1600 each, 4 costing $1200 each, and y costing $900 each, where y is a positive odd integer. what is the greatest possible value of y

Solution:

The median of a group of numbers is the middle number when the group of numbers have been arranged either in ascending of descending other. The median of an even group of numbers is the average of the two most middle most numbers while the median of an odd group of numbers is the middle number.

Since there are 6 computers costing $1600, 4 computers costing $1200 each and y computers costing $900 each. Since y is odd, hence y + 6 + 4 would be odd and the median would be the middle number.

Given that the median price = $1200, this means that the middle of the group of numbers is $1200

900, 900, ..., 1200, 1200, 1200, 1200, 1600, 1600, 1600, 1600, 1600, 1600

Since y is odd, for the median price to be $1200, y has to be 3 or 5.

If y = 3:

900, 900, 900, 1200, 1200, 1200, 1200, 1600, 1600, 1600, 1600, 1600, 1600

median = $1200

If y = 5:

900, 900, 900, 900, 900, 1200, 1200, 1200, 1200, 1600, 1600, 1600, 1600, 1600, 1600

Median = $1200

Therefore the greatest possible value of y is 5

5 0
3 years ago
Evaluate -(2^6)(2^3)
valina [46]

Answer:

- (2^9)

Step-by-step explanation:

-(2^6)(2^3)

We know a^b * a^c = a^( b+c)

- ( 2 ^ (6+3))

- (2^9)

7 0
4 years ago
A botanist wishes to estimate the mean number of seeds for a certain fruit. She samples 11 specimens and finds the average numbe
Aliun [14]

Answer:

a)The 98% of confidence intervals are

Lower bound of CI = 47 -3.82436 = 43.1756

Upper bound of CI = 47 + 3.82436 = 50.8243

b) The conditions are required for the validity of the interval

A) μ known

Step-by-step explanation:

<u>Explanation</u>:-

The given sample size is 'n' =11

Given the average number of seeds is 47 with a standard deviation of 7

Sample mean (x⁻) = 47

Standard deviation (S) = 7

<u>The 98% of confidence intervals are</u>

(x^{-} - t_{0.02} \frac{S}{\sqrt{n} } , x^{-} + t_{0.02}\frac{S}{\sqrt{n} } )

(47 - t_{0.02} \frac{7}{\sqrt{11} } , 47+ t_{0.02}\frac{7}{\sqrt{11} } )

The degrees of freedom = n-1 =11-1 =10

t₀.₀₂= 1.812 ( from t - table)

now the intervals are

(47 - 1.812 \frac{7}{\sqrt{11} } , 47+ 1.812\frac{7}{\sqrt{11} } )

<u>Lower bound of CI = 47 -3.82436 = 43.1756</u>

<u>Upper bound of CI = 47 + 3.82436 = 50.8243</u>

The conditions are required for the validity of the interval

<u>A) μ known</u>

<u>Explanation</u>:-

If a random sample xi of size 'n' has been drawn from a normal population with a specified mean (μ) known.

The limit for  (μ)  is given by

(x^{-} - t_{0.02} \frac{S}{\sqrt{n} } , x^{-} + t_{0.02}\frac{S}{\sqrt{n} } )

5 0
3 years ago
The average turtle swims at 20 km/h and walks at 5 km/h. find the ratio of swimming to walking rates.
Alexus [3.1K]
Swimming / walking = 20 / 5
20 / 5
4

therefore the ratio is 4 : 1
7 0
4 years ago
Read 2 more answers
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