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4 years ago

Find the area of the triangle.

Mathematics

2 answers:

sveticcg [70]4 years ago

7 0

The unknown side measures 12, if you use Pythagorean theorem. Area = length x width / 2. l x w = 108. Then, 108/2 = 54. Area=54ft(squared)

Yakvenalex [24]4 years ago

3 0

A²+B²=C² then do Base x Hight decided by 2.

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the first box measures 8 inches by 6.25 inches by 10.5 inches. the second box measures 9 inches by 5.5 inches by 11.75 inches. W

ira [324]

First Box
V= L*W*H
V=8*6.25*10.5
V=50*10.5
V=525 inches³

<span>Second Box
</span>V=L*W*H
V=9*5.5*11.75
V=49.5*11.5
V=569.25 inches³

8 0

3 years ago

Help me out here please

Paraphin [41]

Answer:

They came to different conclusions because if you graph n+10 and 2n+3, eventually 2n+3 will surpass n+10 (see picture for diagram). Since they both plugged in different numbers for n, they received different answers to the question.

5 0

3 years ago

The volume V of a right‑circular cylinder is computed using the values d = 3.1 m for the diameter and h = 6.6 m for the height.

pantera1 [17]

Answer:

Step-by-step explanation:

A function f(x) can by approximated at and around a point, say x = a by,

f(x) = f(a) + f'(a)(x-a)

where, $f'(x)=\frac{df}{dx}$

Here, volume V is a function of radius r and height h. In the 2 dimensional case, we have to take the partial derivatives.

Given,

$V=\pi r^2h$

or, $dV=\frac{\partial V }{\partial r}dr+ \frac{\partial V }{\partial h}dh$

at r = 1.55 m and h = 6.6 m

$dr=0.02\times1.55m=0.031m$

$dh=0.02\times6.6m=0.132m$

$\frac{\partial V }{\partial r}=2\pi r h=2\pi \times 1.55\times 6.6=64.277$

$\frac{\partial V }{\partial h}=\pi r^2=7.5477$

Therefore, $dV=(64.277\times.031)+(7.5477\times0.132)=2.9889m$

Also, $V=\pi r^2h=49.8147m$

Hence, maximum error is given by,

$R=\frac{2.9889}{49.8147} \times 100$

= 6%

7 0

4 years ago

Find dy/dx<br><br> y = 5/8x^3/7 + 8x^4 + 6x - 9

aleksandrvk [35]

Answer:

15/56x^(-4/7) + 32x^3 + 6.

Step-by-step explanation:

Using the rule for algebraic differentiation:

If y = ax^n, dy/dx = anx^(n-1).

So :

If y = 5/8x^3/7 + 8x^4 + 6x - 9

dy/dx = 5/8* 3/7 x^(3/7-1) + 8*4 x^(4-1) + 6x(1-1)

= 15/56x^(-4/7) + 32x^3 + 6.

5 0

4 years ago

Xsquared+11x+28+xsquared+13x+40

UNO [17]

X² + 11x + 28 + x² + 13x + 40

combine like terms

x² + x² = 2x²
11x + 13x = 24x
28 + 40 = 68

2x² + 24x + 68 is your answer

if you want it simplified:

2(x² + 12x + 34)

hope this helps

5 0

4 years ago