1. Divide wire b in parts x and b-x.
2. Bend the b-x piece to form a triangle with side (b-x)/3
There are many ways to find the area of the equilateral triangle. One is by the formula A=

A=

Another way is apply the formula A=1/2*base*altitude,
where the altitude can be found by applying the pythagorean theorem on the triangle with hypothenuse (b-x)/3 and side (b-x)/6
3. Let x be the circumference of the circle.

so

Area of circle =

4. Let f(x)=

be the function of the sum of the areas of the triangle and circle.
5. f(x) is a minimum means f'(x)=0
f'(x)=

=0



6. So one part is

and the other part is b-
It would be 4/15 is greater.
4/15 = 26% wrong
3/10 = 30% wrong
5x + 8 - 3x = 10
First you can combine the like terms.
5x - 3x + 8 = 10
2x + 8 = 10
- 8 - 8
2x = 2

x=1
This graph is a Quadratic Graph meaning it is a "U" shape. I am unable to help with the transformations since I am unaware of the signs in the problem. But I hope I helped