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Evgen [1.6K]
3 years ago
6

PLEASE HELP ASAP! WILL GIVE BRAINLIEST! I don’t really understand how to do this?

Mathematics
1 answer:
galben [10]3 years ago
4 0

so we're trying to figure what portion of silas' slime is detergent. we know that his slime is a combo of 5 oz glue and 2 oz detergent for a total of 7 oz of slime.

what we want to find is how much of those 7 oz of slime is detergent.

quite simply 2 oz of the 7 is detergent.

to make that into a percent just divide 2 by 7.

2/7 = 0.2857

then move the decimal over two spots to get

28.57 or

D. 28.6%

just remember that percents are just how much makes up the whole.

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Which one is a polynomial?<br> √x-6<br> OR<br> x-√6
Alex17521 [72]

Answer:

  x-√6

Step-by-step explanation:

Non-integer powers of the variable disqualifies the expression from being a polynomial. √x -6 has x to the 1/2 power, so that expression is not a polynomial. Polynomials may have any real or complex, rational or irrational coefficients. (We usually study only polynomials with real coefficients.)

  x-√6 is a polynomial

8 0
4 years ago
Does anyone know how to do this? I’m confused
nikklg [1K]

Answer:

cos(θ)

Step-by-step explanation:

Para una función f(x), la derivada es el límite de  

h

f(x+h)−f(x)

​

, ya que h va a 0, si ese límite existe.

dθ

d

​

(sin(θ))=(  

h→0

lim

​

 

h

sin(θ+h)−sin(θ)

​

)

Usa la fórmula de suma para el seno.

h→0

lim

​

 

h

sin(h+θ)−sin(θ)

​

 

Simplifica sin(θ).

h→0

lim

​

 

h

sin(θ)(cos(h)−1)+cos(θ)sin(h)

​

 

Reescribe el límite.

(  

h→0

lim

​

sin(θ))(  

h→0

lim

​

 

h

cos(h)−1

​

)+(  

h→0

lim

​

cos(θ))(  

h→0

lim

​

 

h

sin(h)

​

)

Usa el hecho de que θ es una constante al calcular límites, ya que h va a 0.

sin(θ)(  

h→0

lim

​

 

h

cos(h)−1

​

)+cos(θ)(  

h→0

lim

​

 

h

sin(h)

​

)

El límite lim  

θ→0

​

 

θ

sin(θ)

​

 es 1.

sin(θ)(  

h→0

lim

​

 

h

cos(h)−1

​

)+cos(θ)

Para calcular el límite lim  

h→0

​

 

h

cos(h)−1

​

, primero multiplique el numerador y denominador por cos(h)+1.

(  

h→0

lim

​

 

h

cos(h)−1

​

)=(  

h→0

lim

​

 

h(cos(h)+1)

(cos(h)−1)(cos(h)+1)

​

)

Multiplica cos(h)+1 por cos(h)−1.

h→0

lim

​

 

h(cos(h)+1)

(cos(h))  

2

−1

​

 

Usa la identidad pitagórica.

h→0

lim

​

−  

h(cos(h)+1)

(sin(h))  

2

 

​

 

Reescribe el límite.

(  

h→0

lim

​

−  

h

sin(h)

​

)(  

h→0

lim

​

 

cos(h)+1

sin(h)

​

)

El límite lim  

θ→0

​

 

θ

sin(θ)

​

 es 1.

−(  

h→0

lim

​

 

cos(h)+1

sin(h)

​

)

Usa el hecho de que  

cos(h)+1

sin(h)

​

 es un valor continuo en 0.

(  

h→0

lim

​

 

cos(h)+1

sin(h)

​

)=0

Sustituye el valor 0 en la expresión sin(θ)(lim  

h→0

​

 

h

cos(h)−1

​

)+cos(θ).

cos(θ)

5 0
3 years ago
Read 2 more answers
Review:
alex41 [277]

Answer:

Step-by-step explanation:

Well 6 to the second power is when you multiply 6 x 6 = 36

And ab= -320

7 0
3 years ago
Solve: x - 2 = x-8<br><br> {11}<br> {6, 11} <br> {}
Darina [25.2K]
The last one since there are no solutions
8 0
3 years ago
Read 2 more answers
[-9,-4] U (-4, 19)<br><br><br> Simplify the following Union and/or intersection
Kay [80]

The union and intersection of the sets is given as  { -4, -9 , 19} and { -4} respectively.

<h3>What is a set?</h3>

A set is simply a  mathematical model for a collection of different things which could be elements or members.

Union of sets represented with '∪' is the combination of two sets without repetition

Intersection of sets represented with '∩' is the sum of elements common between the.

From the expression given, we have;

[-9,-4] U (-4, 19)

= { -4, -9 , 19}

[-9,-4] U (-4, 19)

= { -4}

Thus, the union and intersection of the sets is given as  { -4, -9 , 19} and { -4} respectively.

Learn more about sets here:

brainly.com/question/2166579

#SPJ1

6 0
2 years ago
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