1. The best option is C) pick an object at random, and keep track of how many copies of an object are left in a game.
2. The best option is D) clockwise and counterclockwise.
3. your 3rd question does not seem to be clear to me.
Answer:
Explanation:
The following code is written in Java, the function takes in a list with the previous day's values. The function then uses that list, loops through it and multiplies each individual value by 2 and returns the modified list. The first red square represents the test case for the function, while the second red square in the image represents the output.
public static ArrayList<Integer> doubleIt(ArrayList<Integer> mylist) {
for (int x = 0; x<mylist.size(); x++) {
mylist.set(x, mylist.get(x)*2);
}
return mylist;
}
Answer:
In Python:
def print_volume (r):
volume = 4/3 * 3.142*r**3
print(volume)
print_volume(7)
print_volume(14)
print_volume(22)
Explanation:
This defines the function and takes radius r as the parameter
def print_volume (r):
This calculates the volume
volume = 4/3 * 3.142*r**3
This prints the volume
print(volume)
The next three lines call the function with different values
<em>print_volume(7)</em>
<em>print_volume(14)</em>
<em>print_volume(22)</em>
Java.lang is the answer you're looking for