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igor_vitrenko [27]
3 years ago
5

What is the output of the following program? #include using namespace std; class TestClass { private: int val; void showVal() {

cout << val << endl; } public: TestClass(int x) { val = x; } }; int main() { TestClass test(77); test.showVal(); return 0; }
Computers and Technology
1 answer:
sveticcg [70]3 years ago
5 0

Answer:

The answer to this question is "The program will not compile."

Explanation:

In the given C++ programming language program. The program will not compile because in the program we define a class that is "TestClass" in this class we define a private variable and a function that is val and showVal(). In this function, we print the value of val variable. Then we define a parameterized constructor, in this constructor we use the private variable val that holds the constructor parameter value. Then we define a main function, in the main function we create a class object test which is defined wrong.

That's why the answer to this question is "The program will not compile."  

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Answer:

//here is the statement in java.

import java.util.*;

//class definition

class Solution

{

// main method of the class

public static void main (String[] args) throws java.lang.Exception

{

   try{

    // this statement will print the 3 2 1 Go! and go to newline

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   }catch(Exception ex){

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}

Explanation:

We can use "System.out.println()" to print the required output same as it required. After printing this, it will go to newline.

Output:

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<h3>What is open source?</h3>

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Therefore, The  disclosure paradigm has as its assumptions that an attacker will learn little or nothing from disclosure is known as Open source.

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brainly.com/question/6065176

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2 years ago
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