Answer:
-20/3
Step-by-step explanation:
First simplify the left side of the equation
243^(1/5x)= (243^1/5)^x
=(
)^x
= 3^x
Now that the left side is simplified, let's move to the right side
81^(x+5)=(
)^(x+5) simplify 81 to base 3^4
=
use the product of powers property to multiply the exponents together
=![x^{4x+20](https://tex.z-dn.net/?f=x%5E%7B4x%2B20)
With both sides simplified, let's rewrite the equation, this time in simplified terms
=
x=4x+20 because both the bases are same, their exponential value must also be equal
-3x=20 solve the algebraic equation for x
x=![-\frac{20}{3}](https://tex.z-dn.net/?f=-%5Cfrac%7B20%7D%7B3%7D)
I think it is D. Hi <span>Scolen231p7rzw3</span>
Answer:
102
Step-by-step explanation:
The first step is to find out how to find the next number in the term.
In this we can see that to get to the next number in the term we need to add 5.
The easiest way to figure out the 21st term of this, would be to multiply 5×21. This is equal to 105.
But since we started at three less than 5, we need to subtract 3 from 105. 105-3=102.
The 21st term is 102.
Answer:
x=0
Step-by-step explanation:
Answer:
In arithmetic, variables look like letters.
Step-by-step explanation:
As we know that Mathematical arithmetic deals with numbers and certain properties with them.
Some of the main properties between numbers are as follows:
Variables do not remain constant, so we basically assign a number to a variable with an equal operator denoted by '='.
For example, let us assume a variable x being equal to 7. so it can written as:
![x = 7](https://tex.z-dn.net/?f=x%20%3D%207)
Let suppose the value of the variable x=7 changes to x=10, then the new value will be:
![x = 10](https://tex.z-dn.net/?f=x%20%3D%2010)
Therefore, the correct answer is:
In arithmetic, variables look like letters.