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Galina-37 [17]
3 years ago
15

If the graph of f(x) has the point (2,7) then what is one point that will be on the graph of f-1(x)

Mathematics
2 answers:
IRINA_888 [86]3 years ago
6 0

The graph of f^-1 (x) is called the inverse function of f (x). The relationship between the two is that the point (x,y) is on the graph of f (x) if and only if the point (y,x) is on the graph of f^-1 (x).

This means that if the point (2, 7) is on f (x), therefore the point (7, 2) is on f^-1 (x).

<span>Answer: (7, 2)</span>

Nuetrik [128]3 years ago
5 0

Answer:  The required point is (7, 2).

Step-by-step explanation:  Given that the graph of f(x) has the point (2, 7).

We are to find one point that will be on the graph of f^{-1}(x).

We know that

if a point (a, b) lies on the graph of a function g(x), then the point (b, a) will always lie on the the graph of the inverse function g^{-1}(x).

Therefore, the one point that will lie on the graph of f^{-1}(x) is (7, 2).

Thus, the required point is (7, 2).

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A person invest $10,000 into a bank the bank pays 4.75% interest compounded semi annually. To the nearest 10th of a year, how lo
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T is 13.9 years to the nearest 10th of a year

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In this question, we are to calculate the number of years at which someone who invests a particular amount will have a particular amount based on compound interest.

To calculate the number of years, what we do is to use the compound interest formula.

Mathematically,

A = P(1+ r/n) ^nt

Where A is the final amount after compounding all interests which is $19,200 according to the question

P is the initial amount invested which is $10,000 according to the question

r is the rate which is 4.75% according to the question = 4.75/100 = 0.0475

n is the number of times per year in which interest is compounded. This is 2 as interest is compounded semi-annually

t= ?

we plug these values;

19200 = 10,000(1+0.0475/2)^2t

divide through by 10,000

1.92 = (1+0.02375)^2t

1.92 = (1.02375)^2t

We find the log of both sides

log 1.92 = log [(1.02375)^2t)

log 1.92 = 2tlog 1.02375

2t = log 1.92/log 1.02375

2t = 27.79

t = 27.79/2

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The question asks to give answer to the nearest tenth of a year and thus t = 13.9 years

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