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S_A_V [24]
3 years ago
10

Use the arc length formula and the given information to find r. s = 12 cm, θ = 36°; r = ?

Mathematics
1 answer:
Sveta_85 [38]3 years ago
3 0

Answer:

I guess the radius equals to 19.0985

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sin A = 0.69

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sin A = 20 / 29 = 0.69

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Find the area of this triangle. Round to<br> the nearest tenth.<br> 17 m<br> 35<br> 15 m
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9.73

Step-by-step explanation:

for the second part of the equation, h was supposed to be there instead of x but the height is 9.73

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ABC is reflected over the x-axis. What are the vertices of A'B'C' ?
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Answer please! Find the answer to both questions
SpyIntel [72]

Answer:

  • AP
  • tₙ = (n-2)k² + (2n - 3)k + n

Step-by-step explanation:

<u>Given sequence:</u>

  • -k² - k + 1, k + 2, k² + 3k + 3, 2k² + 5k + 4, ...

We can see apart from the second term all terms are 2nd degree trinomial so it is not a GP.

Let's find the difference: to determine if it is a AP:

  • k + 2 - (-k² - k + 1) = k + 2 + k² + k -1 = k² + 2k + 1
  • k² + 3k + 3 - (k + 2) =  k² + 3k + 3 - k - 2 = k² + 2k + 1
  • 2k² + 5k + 4 - (k² + 3k + 3) = 2k² + 5k + 4 - k² - 3k - 3 = k² + 2k + 1

As we see the difference is common and it confirms the sequence is AP.

<u>First term is </u>

  • a₁= -k² - k + 1

<u>Common difference is </u>

  • d = k² + 2k + 1

<u>nth term is:</u>

  • tₙ = a₁ + (n-1)d
  • tₙ = -k² - k + 1 + (n-1)(k² + 2k + 1) =
  • -k² - k + 1 + (n-1)k² + (n-1)*2k + n-1 =
  • (n-2)k² + (2n - 3)k + n
5 0
3 years ago
Identify the asymptotes of each function.
Studentka2010 [4]

Answer:

It would be x=3, f(x)=0

Step-by-step explanation:

This is because an asymptote is the line where a function is approaching infinity towards.

On the graph, you see that the function it stretching out towards what is x=3, along with the x axis, which is f(x)=0.

4 0
3 years ago
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