Answer:
A tree with a height of 6.2 ft is 3 standard deviations above the mean
Step-by-step explanation:
⇒ statement: A tree with a height of 5.4 ft is 1 standard deviation below the mean(FALSE)
an X value is found Z standard deviations from the mean mu if:
In this case we have:
We have four different values of X and we must calculate the Z-score for each
For X =5.4\ ft
Therefore, A tree with a height of 5.4 ft is 1 standard deviation above the mean.
⇒ statement:A tree with a height of 4.6 ft is 1 standard deviation above the mean.
(FALSE)
For X =4.6 ft
Therefore, a tree with a height of 4.6 ft is 1 standard deviation below the mean
.
⇒ statement:A tree with a height of 5.8 ft is 2.5 standard deviations above the mean
(FALSE)
For X =5.8 ft
Therefore, a tree with a height of 5.8 ft is 2 standard deviation above the mean.
⇒ statement:A tree with a height of 6.2 ft is 3 standard deviations above the mean.
(TRUE)
For X =6.2\ ft
Therefore, a tree with a height of 6.2 ft is 3 standard deviations above the mean.
Answer:
Step-by-step explanation:
It's very simple just divide 21.75 by five and that's your answer did you want me to do it?