Area of the base = pi*(4x+2)^2 = pi*(16x^2 +16x +4)
volume of cylinder = pi*r^2 *h
V = pi *(16x^2 +16x +4)(5x+4) = pi*(80x^3 +80x^2 +20x +64x^2 +64x +16) =
= pi*(80x^3 +144x^2 +84x +16)
than we consider it without pi so result choice A. is right sure
hope helped
Answer:
part A: expression 1: 6(8m+2)
expression 2: 6m+12+42m
Part B: 6(m+2+7m)= 6(8m+2)
combine like terms is 6(m+2+7m), so it is 6(2+8m) or 6(8m+2)
6(8m+2)= 6(8m+2)
Part C: 6m+12+42m=6(m+2+7m)
m=0
6(0+2+7(0))=6(0)+12+42(0)
6(2)= 12
12=12
In a throw of 2 fair dice, there are 6*6=36 equiprobability outcomes.
To get a sum of 5, there are 4 ways, (1,4),(2,3),(3,2),(4,1) with probability of 4/36=1/9
To get at least one 5, there are 6+6-1=11 outcomes (note (5,5) has been counted in both, so subtracted from sum). The probability is 11/36
Since the two events are mutually exclusive (once we have a five, the sum can no longer be 5), we can add the probabilities to get the probability of one event or the other.
P(sum of 5 OR at least one 5)=1/9+11/36=4/36+11/36=15/36=5/9
1. B, dependent variable
2. C, the dependent variable is represented in the 2nd column of a table.
8.
A. Domain: { 0, -3, 4, 5 }
B. Range: { 0, 1, 6, 7, 8 }
C. No, this is not a function because the x-value of 4 (domain) has two corresponding y-values of 6 and 8 (range)
