during a pie eating contest daniel ate 3 3/4 pies and diego ate 2 2/3 pies how many pies did they eat altogether?

The price of a pizza plus 12% delivery charge comes to a total cost of $17.92. What was the price of the pizza?

Leya [2.2K]

Answer:

i believe the answer is 14.93 dollars.

Step-by-step explanation:

3 0

2 years ago

The length of a rectangle 4 yd is longer than its width. If the perimeter of the rectangle is 68 yd, find its length and width.

natulia [17]

w + 4

------------------------

l l

l l w

l l

------------------------

Perimeter would be the sum of all the sides so: (w+4) + w + (w+4) + w

Perimeter is 60 yards according to your problem so: (w+4) + w + (w+4) + w = 60 yds

1.Simplify/combine like terms:

w + 4 + w + w + 4 + w =

4w + 8 =

Now it's a 2-step algebra equation

4w + 8 = 60

2.Subtract 8 on both sides

4w = 56

3.Divide both sides by 4

w = 14

4 0

3 years ago

The difference between the product of 4 and a number 6

Mice21 [21]

Answer:

If we call our unknown value x, then we can say that

The "product of 4 and a number" is 4x

The "difference between" 4x and 6 is 4x - 6

Step-by-step explanation:

8 0

3 years ago

Six equilateral triangles are connected to create a regular hexagon. The area of the hexagon is 24a2 – 18 square units. Which is

shusha [124]

It would be 6(4a2 - 3)
you would factor out just the 6 because the 18 doesn’t a a term with it like 34a2 does. then just divide normally to get ur answer 6(4a2 - 3)

3 0

3 years ago

Walk fifty meters at 30o north or east from the old oak tree. (2) Turn 45o to your left (you should now be facing 75o north of e

saw5 [17]

Answer:

A straight line of approximately 75 meters, 1.4º north

Step-by-step explanation:

Hi, let's make it step by step to make it clearer

1) If we walk 50 meters in 30º angle Northeast, assuming the Old Oak tree is the point 0,0 and we're dealing with vectors in $R^{2}$ . To say 30º Northeast is 30º clockwise (or 60º counter clockwise).

2) Then there was a the turning point to the left. If I turn to the left, on my compass 45º , I'll face 75º northeast.

3) Finally, the last vector leads to the treasure from the Old Oak Tree, i.e. the resultant.

So, let's calculate the norm which is the length of the each vector.

1) Graphing them we can find the points, then the components and then calculate the norm, the length of each vector.

Since the Oak Tree is on (0,0). The turning point (50,86.61) and the Rock (R=(1.4,74,85) we can write the following vectors:

$\vec{u}=\left \langle 50,86.61 \right \rangle\\\vec{v}=\left \langle -48.6,-11.76\right \rangle\\\vec{w}=\left \langle 1.4,74.85 \right \rangle$

Now, let's calculate each vector length by calculating the norm.

$\left \| \vec{u} \right \|=\sqrt{50^{2}+86.6^2}=100\\\left \| \vec{v} \right \|=\sqrt{(-48.6)^2+(-11.76)^2}=50\\\left \| \vec{u} \right \|=\sqrt{(1.4)^2+(74.85)^2}=74.86$

The path is almost 75 meters. And since it is less than 15º degrees to the left of the North (or to the right) its direction is still north of the Old Oak Tree.

8 0

3 years ago