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Natalija [7]
3 years ago
6

What do I select? Please answer it is very hard for me

Mathematics
1 answer:
Kamila [148]3 years ago
5 0

Answer:

-9(4h)

Step-by-step explanation:

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A line passes through (9, –9) and (10, –5).Write an equation for the line in point-slope form.
CaHeK987 [17]
Y - y1 = [-9-(-5)]/[(9-10] * (x - x1)

y - (-9) = [-9 + 5] / [-1] * (x - 9)

y + 9 = (-4) / (-1) * (x - 9)

y + 9 = 4(x - 9)

y + 9 = 4x - 36

y = 4x - 36 - 9

y = 4x - 45  This is the slope - intercept form.

y - 4x + 45 = 0 This is the standard form
5 0
3 years ago
write the ratios sin m, cos m, and tan m. give the exact value and four decimal approximation. Please help.
Rom4ik [11]
Given,
hypotenuse = 23
adjacent = 4sqrt19
opposite = 15
then, using sohcahtoa,
sin m = 15/23 =0.652
cos m = 4sqrt19/23 = 0.758
tan m = 4sqrt19/15 = 1.162
7 0
3 years ago
The answer is below PLEASE HELP IM BEING TIMED I WILL MARK BRAINLIEST IF RIGHT
Fudgin [204]
15x+30y-220
Here is the work:

3 0
3 years ago
PLEASE HELP!!!!!
frez [133]

Answer:   (-4,-5)                        

Step-by-step explanation:

Here ABCD is a parallelogram,

Where A≡(-2,-1), B≡(2,1), C≡(0,-3) and D≡(x,y)

By the property of parallelogram,

AB║CD, AD║BC, AB = CD and AD=BC

If AB ║ CD

⇒ Slope of AB = Slope of CD

⇒ \frac{1-(-1)}{2-(-2)} = \frac{-3-y}{0-x}

⇒ \frac{1+1}{2+2)} = \frac{-3-y}{-x}

⇒ \frac{2}{4} = \frac{3+y}{x}

⇒ x=6+2y ------ (1)

Now, AB = CD

\sqrt{(2-(-2))^2+(1-(-1))^2} = \sqrt{(0-x)^2+(-3-y)^2}

\sqrt{4^2+2^2} = \sqrt{x^2+9+6y+y^2}

\sqrt{16+4} = \sqrt{x^2+9+6y+y^2}

\sqrt{20} = \sqrt{x^2+9+6y+y^2}

20 = x^2+9+6y+y^2

x^2+6y+y^2=11

From equation (1)

(6+2y)^2+6y+y^2=11

36+4y^2+24y+6y+y^2=11

5y^2+30y+25=0

y^2+6y+5=0

⇒ y = -1 or -5

Again by equation (1)

for y = -1, x = 4

For y = -5, x = -4

Thus the coordinate of D are (4,-1) or ( -4,-5)

But for D≡(4,-1), AD∦BC

While For D≡(-4,-5) AD ║ BC

Thus the coordinates of D are ( -4,-5)

7 0
3 years ago
yesterday jamal scored -20 points on a puzzle today he scored more points use absolute value to describe today's score as a loss
serious [3.7K]
Absolute value is never negative so the answer is 20
6 0
4 years ago
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