<span>the rate of decay each month can calculated using the following formula:
</span><span>
6%/year × 1 year/(12 months) = 0.5%/month
0.06 x 1/12 = 0.005/month
</span><span>So the 0.5% is the right answer.
I hope it helped.</span>
Answer:
i think probably 20
Step-by-step explanation:
if 200 students, students do not prefer math 10/100 × 200 = 20
Hello!
To find how many times greater his average is, we just divide.
185.4/122.9≈1.51
Therefore, his average is about 1.51 times greater than Lola's.
I hope this helps!
Answer:
![x=e^{2} -4](https://tex.z-dn.net/?f=x%3De%5E%7B2%7D%20-4)
Step-by-step explanation:
Divide both sides by 5:
![log(x+4)=\frac{10}{5} \\log(x+4)=2](https://tex.z-dn.net/?f=log%28x%2B4%29%3D%5Cfrac%7B10%7D%7B5%7D%20%5C%5Clog%28x%2B4%29%3D2)
Cancel logarithms by taking exp of both sides:
![e^{log(x+4)}=e^{2} \\x+4=e^{2}](https://tex.z-dn.net/?f=e%5E%7Blog%28x%2B4%29%7D%3De%5E%7B2%7D%20%20%5C%5Cx%2B4%3De%5E%7B2%7D)
Solve for x subtracting 4 from both sides:
![x=e^{2} -4](https://tex.z-dn.net/?f=x%3De%5E%7B2%7D%20-4)
Answer:
5c+4p = 18.50
2c+4p = 11.20
Cost of cup = $2.4
cost of pretzels = $1.625
Step-by-step explanation:
Note:
2 cups of hot cocoa and 4 pretzels for $11.30
Computation:
5c+4p = 18.50........eq1
2c+4p = 11.30........eq2
Where c = cost of cup
p = cost of pretzels
From eq1 - eq2
3c = 7.20
c = 2.4
Cost of cup = $2.4
5c+4p = 18.50
5(2.4) + 4p = 18.50
p = 1.625
cost of pretzels = $1.625