Answer:
m=18
Step-by-step explanation:
18 is the correct value for +5
Answer: they have 68 servings of ice cream left for the party
Step-by-step explanation:
The Smiths purchased 6 containers of ice cream for a party. Each container holds 9 cups of ice cream. This means that the total number of cups of ice cream that they have is
6 × 9 = 54 cups
Before the party, their sons ate 3 cups of ice cream altogether. This means that the number of cups of ice cream that they have left is
54 - 3 = 51 cups
One serving is 3/4 cup of ice cream. This means that the number of serving that they have left is
51/0.75 = 68
The <em><u>correct answers</u></em> are:
The inequality is 75+4t ≥ 400, and they must sell at least 82 tickets.
Explanation:
t is the number of tickets sold. They start out with $75, so that is where our inequality begins. Each ticket is $4; this gives us the expression 4t. Together with the $75 carry over, we have 75+4t.
They must make at least $400 to pay for the dance. This means it must be more than or equal to 400; this gives us 75+4t ≥ 400.
To solve this, first subtract 75 from each side:
75+4t-75 ≥ 400-75
4t ≥ 325
Divide both sides by 4:
4t/4 ≥ 325/4
t ≥ 81.25
We cannot sell a portion of a ticket, so we round. While mathematically this number would "round down," if they only sell 81 tickets, they will not have enough money. Therefore we round up to 82.
Notice the picture
the rhombus, or kite, is really just 4 triangles
all sides are the same lenght in a rhombus,
thus, find the area of all of the triangles,
and you already have two sides given,
and then, add them up
or just find the length of one, and multiply times 4 :)
recall, area of a triangle = 1/2 bh
Answer:
Option D is correct that is The Slopes of two lines are negative reciprocals.
Step-by-step explanation:
Perpendicular lines are the lines which intersect each other at right angle or make 90° angle with each other.
we that the Slope of perpendicular lines are equal to -1
Therefore, Option D is correct that is The Slopes of two lines are negative reciprocals.
