I need help, I don't quite understand

Mathematics

2 answers:

maksim [4K]2 years ago

5 0

Answer:

Step-by-step explanation:

so we have:

f+2>5 2 goes the other side, so

f>5-2

f>3

f+4<9 4 goes to the other side, so

f<9-4

f<5

we have two inequality

f>3

f<5

f belongs (3,5), we have only one value for this, it is 4

OverLord2011 [107]2 years ago

3 0

F can be equal to both 1 and 2. Reason why: If you input 1 or 2 to replace f on either inequality, it will never be greater than or equal to 5 or 9.

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lutik1710 [3]

The answer is 6 positive tiles.

4 0

2 years ago

What two numbers add to 8 and multiply to 28

anygoal [31]

Find numbers that multiply to 28 and add them to see if they add to 8
28=
1 and 28=29 not 8
2 and 14=16 not 8
4 and 7=11 not 8
that's it'
no 2 numbers
we must use quadratic formula

x+y=8
xy=28

x+y=8
subtract x fromb oths ides
y=8-x
subsitute
x(8-x)=28
distribute
8x-x^2=28
add x^2 to both sides
8x=28+x^2
subtract 8x
x^2-8x+28=0

if you have
ax^2+bx+c=0 then x= $\frac{-b+/- \sqrt{b^{2}-4ac} }{2a}$
so if we have
1x^2-8+28=0 then
a=1
b=-8
c=28

x= $\frac{-(-8)+/- \sqrt{(-8)^{2}-4(1)(28)} }{2(1)}$
x= $\frac{8+/- \sqrt{-48} }{2}$
x= $\frac{8+/- 4 \sqrt{-3} }{2}$
x= $4+/- 2 \sqrt{-3}$
x= $4+/- 2i \sqrt{3}$
there are no real numbers that satisfy this

5 0

3 years ago

8x^3-8x=1<br> Solve for x

Anit [1.1K]

Step-by-step explanation:

Step-by-step explanation:

\begin{gathered} \frac{8x - 3}{3x} = 2 \\ 8x - 3 = 6x \\ 8x - 6x = 3 \\ 2x = 3 \\ x = \frac{3}{2} \end{gathered}

8x−3

8x−3=6x

8x−6x=3

2x=3