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Sholpan [36]
3 years ago
5

I need help, I don't quite understand

Mathematics
2 answers:
maksim [4K]3 years ago
5 0

Answer:

1

Step-by-step explanation:

so we have:

f+2>5 2 goes the other side, so

f>5-2

f>3

f+4<9 4 goes to the other side, so

f<9-4

f<5

we have two inequality

f>3

f<5

f belongs (3,5), we have only one value for this, it is 4

OverLord2011 [107]3 years ago
3 0
F can be equal to both 1 and 2. Reason why: If you input 1 or 2 to replace f on either inequality, it will never be greater than or equal to 5 or 9.
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7 0
3 years ago
1. f(x) = 3x – 2; f(4)??
netineya [11]

Answer:

the answer is 5

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8 0
3 years ago
Read 2 more answers
Type the correct answer in each box. A circle is centered at the point (5, -4) and passes through the point (-3, 2). The equatio
Galina-37 [17]

Answer:

(x+ \boxed{-5})^2+(y+\boxed4)^2=\boxed{100}

Step-by-step explanation:

Given:

Center of circle is at (5, -4).

A point on the circle is (x_1,y_1)=(-3, 2)

Equation of a circle with center (h,k) and radius 'r' is given as:

(x-h)^2+(y-k)^2=r^2

Here, (h,k)=(5,-4)

Radius of a circle is equal to the distance of point on the circle from the center of the circle and is given using the distance formula for square of the distance as:

r^2=(h-x_1)^2+(k-y_1)^2

Using distance formula for the points (5, -4) and (-3, 2), we get

r^2=(5-(-3))^2+(-4-2)^2\\r^2=(5+3)^2+(-6)^2\\r^2=8^2+6^2\\r^2=64+36=100

Therefore, the equation of the circle is:

(x-5)^2+(y-(-4))^2=100\\(x-5)^2+(y+4)^2=100

Now, rewriting it in the form asked in the question, we get

(x+ \boxed{-5})^2+(y+\boxed4)^2=\boxed{100}

4 0
3 years ago
What time is it when the hour hand is a little past the 3 and the minite hand is pointing to the 3?
Lisa [10]
3:15 because its till 3 o'clock and in each 1 theres 5 inside so 3x 5 = 15.
Thats how I got the answer 3:15 o'clock.

Hoped it help! :D
4 0
3 years ago
Read 2 more answers
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