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Over [174]
3 years ago
6

An individual who displays the disease sickle-cell anemia must have inherited the deleterious allele from both phenotypically no

rmal parents. This individual is therefore
Biology
2 answers:
Phantasy [73]3 years ago
6 0

Answer: The individual is homozygous recessive.

Explanation:

Sickle cell anaemia is an inherited blood disorder in which there is not much available red blood cells to carry oxygen.

The individual is homozygous recessive because such inherited the two deleterious allele SS.

For an individual to have inherited sickle cell anaemia from the parents, it means the two parents are carriers.

The father have AS gene and the mother have AS gene which is the carrier of sickle cell anaemia gene, the individual inherited the deleterious alleles from the phenotypically normal parents.

Dvinal [7]3 years ago
5 0

Answer:

Homozygous recessive

Explanation:

The parents of the individual displaying the sickle cell anemia (SS) are phenotypically normal parents meaning, both parents are carriers of the (AS) gene which is a recessive trait for sickle cell anemia.

The individual took up the SS allele from both parents which makes him/her homozygous recessive. An individual is said to be homozygous recessive if that individual carries two copies of the same recessive allele.

Homozygous dominant is when an individual carries two copies of the same dominant allele (e.g AA).

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If eaten both the fish and predator will die? *
cestrela7 [59]

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The shark wont die unless it is hurt very badly by the puffer fish. The puffer fish is able to kill all of the animals listed but the puffer fish wouldn't die if he uses his abilities. I would say the sting ray.

Explanation:

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Mars had an orbital period of 1.88 years. In two or more complete sentences,explain how to calculate the average distance from m
Vanyuwa [196]
This is an interesting problem involving astronomy, in fact, simple physics.
Let r=distance of sun to mars, in metres

<span>Mars had an orbital period of 1.88 years.
=>
tangential velocity, v, of the planet, in m/s is
v=\frac{2\pi{r}}{T}
</span>=\frac{2\pi{r}}{1.88*365.25*86400} m/s, accounting for leap years
=3.371*10^{-8}\pi{r}   m/s

The centripetal force, Fc, generated is
Fc=\frac{mv^2}{r}   
        where m=mass of mars = 6.39*10^(24) kg
=\frac{mv^2}{r}
=\frac{6.39*10^{24}v^2}{r}
=7.26168*10^9\pi^2r

The gravitation pull from the sun, Fg, is given by
Fg=\frac{GMm}{r^2}
    where G=grav. const., =6.67408*10^(-11) m^3<span> kg^(</span>-1)<span> s^(</span>-2)
              M=mass of sun=1.989*10^(30) kg
=\frac{6.67408*10^{-11}1.989*10^{30}6.39*10^{24}}{r^2}
=\frac{8.4826*10^44}{r^2}

Since the radial distance is in equilibrium, the average distance, r can be found by equation Fc=Fg and solving for r:
Fc=Fg
=>
7.26168*10^9\pi^2r=\frac{8.4826*10^44}{r^2}
Solving for the real root:
r^3=\frac{8.48256*10^44}{7.26168*10^9*%pi^2}
=\frac{1.1681263*10^{35}}{\pi^2}
=2.279*10^11 m


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