Answer:
The molality is 0.504 molal
Explanation:
Step 1: Data given
Mass of NaCl = 25.00 grams
Molar mass NaCl = 58.44 g/mol
Mass of water = 850.0grams
Step 2: Calculate moles NaCl
Moles NaCl = mass NaCl / molar mass NaCl
Moles NaCl = 25.0 grams / 58.44 g/mol
Moles NaCl = 0.428 moles
Step 3: Calculate molality
Molality = moles NaCl / mass H2O
Molality = 0.428 moles / 0.850 kg
Molality = 0.504 molal
The molality is 0.504 molal
<span>4.97 atm for anyone else stuck on this question
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Answer:
.0027 M
Explanation:
We must calculate the threshold concentration of PO3−4 using Ksp and the given concentration of Ca2+:
Ca3(PO4)2(s)⇌3Ca2+(aq)+2PO3−4(aq)
Ksp=8.6×10−19=[Ca2+]3[PO3−4]2=(4.9×10−5M)3[PO3−4]2
[PO3−4]=0.0027 M
Answer:
4 M
Explanation:
Molarity refers to the molar concentration of a substance (solution). It can be calculated by using the formula below:
Molarity (M) = number of moles (n) ÷ volume (V)
According to the information provided in this question;
V = 0.4 liter
n = 1.6 moles
Molarity = n/V
Molarity = 1.6/0.4
Molarity = 4 M