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2 years ago

The repeating pattern of a mineral’s particles forms a solid called a(n)

Chemistry

2 answers:

natali 33 [55]2 years ago

8 0

Answer:

The answer is a

Explanation:

bazaltina [42]2 years ago

6 0

Crystalline solids are solids that have particles arranged in a regular, repeating patterns. They are held together by uniform intermolecular forces. The faces intersect at a specific angle that identifies that substance. They have distinctive internal structures that in turn lead to distinctive flat surfaces. These flat surfaces give a short rage order. When exposed to x – ray diffractometers, they exhibit a distinctive pattern used to identify the material. They give the same face when you turn a crystalline solid around. The answer is crystal.

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Help me with this question please

Natasha_Volkova [10]

Answer:

I dont know sorry i will try my best htough

Explanation:

7 0

2 years ago

Free-energy change, ΔG∘, is related to cell potential, E∘, by the equationΔG∘=−nFE∘where n is the number of moles of electrons t

mart [117]

Answer:

a) $\Delta G=372490 J$

b) $\Delta G=-568614 J$

Explanation:

a) The reaction:

$Mg(s) +Fe^{2+}(aq) \longrightarrow Mg^{2+}(aq) + Fe(s)$

The free-energy expression:

$\Delta G=-n*F*E$

$E=E_{red}-E_{ox]$

The element wich is reduced is the Fe and the one that oxidates is the Mg:

$-0.44V=E_{red}-(-2.37V)=1.93V$

The electrons transfered (n) in this reaction are 2, so:

$\Delta G=-2mol*96500 C/mol * 1.93 V$

$\Delta G=-372490 J$

b) If you have values of enthalpy and enthropy you can calculate the free-energy by:

$\Delta G=\Delta H - T* \Delta S$

with T in Kelvin

$\Delta G=-675 kJ*\frac{1000J}{kJ} - 298K*-357 J/K$

$\Delta G=-568614 J$

7 0

2 years ago

When excess dilute hydrochloric acid was added to sodium sulphite 960 of sulphuric (iv) oxide was produced. calculate the mass o

irakobra [83]

The mass of sodium sulfite that was used will be 1,890 grams.

<h3>Stoichiometric problems</h3>

First, the equation of the reaction:

$NaSO_3 + 2HCl --- > NaCl_2 + H_2O + SO_2$

The mole ratio of SO2 produced and sodium sulfite that reacted is 1:1.

Mole of 960 grams SO2 = 960/64 = 15 moles

Equivalent mole of sodium sulfite that reacted = 15 moles

Mass of 15 moles sodium sulfite = 15 x 126 = 1,890 grams

More on stoichiometric problems can be found here: brainly.com/question/14465605

#SPJ1

3 0

1 year ago

Sodium carbonate reacts with silver nitrate according to the following balanced equation: Na2CO3 (s) + 2 AgNO3 (aq) → Ag2CO3 (s)

klemol [59]

Answer:

a) 2.01 g

Explanation:

Na₂CO₃ (s) + 2AgNO₃ (aq) → Ag₂CO₃ (s) + 2NaNO₃

First we convert 0.0302 mol AgNO₃ to Na₂CO₃ moles, in order to calculate how many Na₂CO₃ moles reacted:

0.0302 mol AgNO₃ * $\frac{1molNa_2CO_3}{2molAgNO_3}$ = 0.0151 mol Na₂CO₃

So the remaining Na₂CO₃ moles are:

0.0340 - 0.0151 = 0.0189 moles Na₂CO₃

Finally we convert Na₂CO₃ moles into grams, using its molar mass:

0.0189 moles Na₂CO₃ * 106 g/mol = 2.003 g Na₂CO₃

The closest answer is option a).

8 0

3 years ago

In a chemical equation

djverab [1.8K]

Answer:

Answer in explanation

Explanation:

A. This is wrong. The reactants are on the left side of the yields arrow

B. This is wrong. They can only be at one side at a time. They cannot be on both sides at the same time.

C. The products are on the right side of the yields arrow and not at the left side

D. This is correct. The reactants are on the left side of the yields arrow.

E. This is correct. We can have varying numbers of the number of atoms on both side of the yields arrow. The numbers may differ until we decide to balance the equation

4 0

3 years ago