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3 years ago

The repeating pattern of a mineral’s particles forms a solid called a(n)

Chemistry

2 answers:

natali 33 [55]3 years ago

8 0

Answer:

The answer is a

Explanation:

bazaltina [42]3 years ago

6 0

<span>Crystalline solids are solids that have particles arranged in a regular, repeating patterns. They are held together by uniform intermolecular forces. The faces intersect at a specific angle that identifies that substance. They have distinctive internal structures that in turn lead to distinctive flat surfaces. These flat surfaces give a short rage order. When exposed to x – ray diffractometers, they exhibit a distinctive pattern used to identify the material. They give the same face when you turn a crystalline solid around. The answer is crystal.</span>

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3 years ago

What are 5 responsibilities a citizen has in taking part in public affairs

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3 years ago

Percentage yield of sodium peroxide if 5 g of sodium oxide produces 5.5 g of sodium peroxide

Rama09 [41]

<h3>Answer:</h3>

87.40 %

<h3>Explanation:</h3>

Concept being tested: Percent yield of a product

We are given;

Mass of Sodium oxide 5 g

Experimental or Actual yield of sodium peroxide IS 5.5 g

We are required to calculate the percent yield of sodium peroxide;

The equation for the reaction that forms sodium peroxide is

2Na₂O + O₂ → 2Na₂O₂

<h3>Step 1; moles of sodium oxide</h3>

Moles = mass ÷ molar mass

Molar mass of sodium oxide is 61.98 g/mol

Therefore;

Moles = 5 g ÷ 61.98 g/mol

= 0.0807 moles

<h3>Step 2: Theoretical moles of sodium peroxide produced </h3>

From the equation, 2 moles of sodium oxide produces 1 mole of sodium peroxide.

Thus, moles of sodium peroxide used is 0.0807 moles

<h3>Step 3: Theoretical mass of sodium peroxide used</h3>

Mass = Number of moles × Molar mass

Molar mass of sodium peroxide = 77.98 g/mol

Therefore;

Theoretical mass = 0.0807 moles × 77.98 g/mol

= 6.293 g

Theoretical mass of Na₂O₂ is 6.293 g

<h3>Step 4: Percent yield of Na₂O₂</h3>

We know that percent yield is given by the ratio of actual yield to theoretical yield expressed as a percentage.

$Percent yield=(\frac{Actual yield}{theoretical yield})100$

$Percent yield(Na_{2}O_{2})=(\frac{5.5g}{6.293g})100$

= 87.40 %

Therefore, the percentage yield of sodium peroxide is 87.4%

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3 years ago

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Arada [10]

The answer is TRUE.

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2 years ago

Read 2 more answers

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noname [10]

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3 years ago