Mass of KCl= 1.08 g
<h3>Further explanation</h3>
Given
1 g of K₂CO₃
Required
Mass of KCl
Solution
Reaction
K₂CO₃ +2HCl ⇒ 2KCl +H₂O + CO₂
mol of K₂CO₃(MW=138 g/mol) :
= 1 g : 138 g/mol
= 0.00725
From the equation, mol ratio K₂CO₃ : KCl = 1 : 2, so mol KCl :
= 2/1 x mol K₂CO₃
= 2/1 x 0.00725
= 0.0145
Mass of KCl(MW=74.5 g/mol) :
= mol x MW
= 0.0145 x 74.5
= 1.08 g
Formula:

Given:
Density=3.4
Volume=500.0
Plug them into the formula:
Final answer: 1700g
Answer:
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Energy absorbed from
changing the phase of a substance from the liquid phase to gas phase can be
calculated by using the specific latent heat of vaporization. Calculation are
as follows:
<span> Energy = 1.35 mol CCl4 ( 153.81 g / 1 mol ) x 197.8 J/g </span>
<span>Energy = 41071.88 J</span>