The answer is A since: 3^2+4^2=5^2
25=25
The range of y = x^2 is the set of nonnegative numbers. The same applies to y = 2x^2 as well. Shift everything up three units to get y = 2x^2+3
So the range is the set of numbers y such that

The final answer is choice C.
The function is already factored, so it equals zero if and only if one of its factors equals zero:

or

Since -2 is smaller than -3/2 the solutions are -2 and -3/2
Hello,
2x^3+14x^2+6x+42=2x^2(x+7)+6(x+7)
=(x+7)(2x²+6)
=2(x+7)(x²+3) in IR.
or In C 2(x+7)(x-i√3)(x+i√3)