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stepladder [879]

3 years ago

6

A flying squirrel lives in a nest that is 12 meters high in a tree. To reach a fallen acorn that is 16 meters from the base of t

he tree, how far will the flying squirrel have to glide?

1 answer:

Greeley [361]3 years ago

4 0

Pythagorean theorem

12²+16²=c²

√400=c

c=20

20 meters

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Sarah's hair appointment is 30 miles away. How fast must she travel to get there in 60 minutes?

Fudgin [204]

Answer:

30 miles an hour

Step-by-step explanation:

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3 years ago

A total of $98,000 is to be invested, some in bonds and some in certificates of deposit (CDs). If the amount invested in bonds

mamaluj [8]

B= 2000 + CD
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Sophia is 38 inches tall. Her mom is 5 feet tall. How many inches taller is Sophia's mom?

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3 years ago

Read 2 more answers

Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth.

Rzqust [24]

Answer:

a = 6 or 9

Step-by-step explanation:

The "a", "b", and "c" of the quadratic formula are the coefficients of a², a, and the constant term in the given equation:

... a = 2, b = -30, c = 108

Then the quadratic formula tells you the solutions are ...

... (-b ± √(b² -4ac))/(2a)

... = (-(-30) ± √((-30)² -4(2)(108)))/(2(2))

... = (30 ± √(900 -864))/4

... = (30 ± √36)/4

... = (30 ± 6)/4 = {24, 36}/4

... = {6, 9}

_____

The <em>a</em> variable should not be confused with the "a" that is used to name the coefficient of the square of the variable in the quadratic formula. If it is too confusing, rewrite one or the other. For example, you could write ...

... The solution to pa² +qa +r = 0 is ... a = (-q ± √(q²-4pr))/(2p)

where p=2, q=-30, r=108 in the given equation.

5 0

3 years ago

If a tank holds 5000 gallons of water, which drains from the bottom of the tank in 40 minutes, then Torricelli's Law gives the v

pochemuha

Answer:

V'(t) = $-250(1 - \frac{1}{40}t)$

If we know the time, we can plug in the value for "t" in the above derivative and find how much water drained for the given point of t.

Step-by-step explanation:

Given:

V = $5000(1 - \frac{1}{40}t )^2$ , where 0≤t≤40.

Here we have to find the derivative with respect to "t"

We have to use the chain rule to find the derivative.

V'(t) = $2(5000)(1 - \frac{1}{40} t)d/dt (1 - \frac{1}{40}t )$

V'(t) = $2(5000)(1 - \frac{1}{40} t)(-\frac{1}{40} )$

When we simplify the above, we get

V'(t) = $-250(1 - \frac{1}{40}t)$

If we know the time, we can plug in the value for "t" and find how much water drained for the given point of t.

4 0

3 years ago