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3 years ago

Pls help ill give brainliest !!

Mathematics

2 answers:

AnnyKZ [126]3 years ago

4 0

Answer:

Step-by-step explanation:

Luba_88 [7]3 years ago

4 0

$\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}$

Actually Welcome to the Concept of the linear equations.

so we solve here as,

==> -4(-2y+3)=20

==> 8y -12 = 20

==> 8y = 20+12

==> 8y = 32

==> y = 4

hence value of y = 4 .

You might be interested in

If g(x) =4x+2 and f(x) =3x-10 <br><br> find g(f(3))

Leya [2.2K]

Answer:

$g(f(3))=-2$

Step-by-step explanation:

So we have the two functions:

$g(x)=4x+2\text{ and } f(x)=3x-10$

And we want to find g(f(3)).

So, let's find f(3) first:

$f(3)=3(3)-10$

Multiply:

$f(3)=9-10$

Subtract:

$f(3)=-1$

Therefore, we can substitute -1 for f(3):

$g(f(3))=g(-1)$

Now, find g(-1):

$g(-1)=4(-1)+2$

Multiply:

$g(-1)=-4+2$

Add:

$g(-1)=-2$

And we're done!

So:

$g(f(3))=-2$

6 0

4 years ago

.can you help please

sweet [91]

Answer:

38.81cm³

Step-by-step explanation:

Volume of a sphere = 4/3πr³

Diameter is 4.2

radius= 4.2/2 = 2.1 or 21/10

4/3 × 22/7 × 21/10 × 21/10 × 21/10

= 4851/125

= 38.808

≈38.81cm³

3 0

3 years ago

One angle measures 27° more than 2 times another. If the two angles are complementary, find the measures of the angles.

zepelin [54]

Answer:

Step-by-step explanation:

If you work by process of elimination all you have to do is take 27 away from the bigger degree of the two and see if it is 2x as much as the smaller degree.

Ex.

1. 69°-27°= 42°, which is 2x as many as 21°.

8 0

3 years ago

Write a polynomial function of least degree with integral coefficients that has the

frutty [35]

A polynomial function of least degree with integral coefficients that has the

given zeros $f(x)=x^4+x^3+9x^2+9x$

Given

Given zeros are 3i, -1 and 0

complex zeros occurs in pairs. 3i is one of the zero

-3i is the other zero

So zeros are 3i, -3i, 0 and -1

Now we write the zeros in factor form

If 'a' is a zero then (x-a) is a factor

the factor form of given zeros

$\:\left(x-3i\right)\left(x-\left(-3i\right)\right)\left(x-0\right)\left(x-\left(-1\right)\right)\\\left(x-3i\right)\left(x+3i\right)\left(x-0\right)\left(x+1\right)$