Answer:
the time of motion of the ball is 6.89 ms.
Explanation:
Given;
angular speed, ω = 38 rad/s
angular distance, θ = 15 degrees
Angular distance in radian;

Time of motion is calculated as;

Therefore, the time of motion of the ball is 6.89 ms.
Answer:
Torque = –207.4 Nm
Explanation:
Given M = 3.2kg, r = 5.4m, α = –12rad/s² (it is slowing down)
Torque = I × α
α = angular acceleration
I = moment of inertia
I = MR² for a circular hoop
Torque = 3.2×5.4×(– 12)
Torque = –207.4 Nm
Chemical Potential Energy > Electrical Energy > Light Energy + Heat Energy
To calculate the number of sig figs
1. Count ALL nonzero numbers
2. If the zero is between 2 numbers, count it
3. If in a decimal the zero is at the end, count it
4. In a decimal all the zeros before the first nonzero number are placeholders and don't count them
5. In a number greater than zero all zeros AFTER the last nonzero number are placeholders and don't count them.
A - 5
B - 2
C - 3
D - 1
E - 4