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velikii [3]
3 years ago
8

.

Physics
1 answer:
Sergio039 [100]3 years ago
6 0

Answer:

The correct answer is B

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Write 8.54 x 103 in standard notation<br> a. 854,000<br> b. 85,400<br> c. 8,540<br> d. 854
weeeeeb [17]
B. 8540, (assuming you meant 8.54 x 10 to the power 3) you move the decimal point 3 places to the right, if the decimal point can't pass any more numbers add zeros. If it confuses you to think of it this way do 10 cubed first, i.e. 10 x 10 x10 = 1000 and then do 8.54 x 1000 if thats easier for you.
5 0
3 years ago
Three bulbs are connected by tubing, and the tubing is evacuated. The volume of the tubing is 45.0 mL. The first bulb has a volu
kipiarov [429]

Answer:

The final pressure of the whole system is 34.80 atm.

Explanation:

Given that,

Volume = 45.0 ml

Volume of first bulb = 77.0 mL

Pressure  = 8.89 atm

Volume of second  bulb = 250 mL

Pressure = 2.82 atm

Volume of third  bulb = 21.0 mL

Pressure = 8.42 atm

We need to calculate the final pressure of the whole system

Using formula of pressure

P_{1}V_{1}+P_{2}V_{2}+P_{3}V_{3}+P_{t}V_{t}=P_{f}V_{f}

Where, P_{1}= pressure of first bulb

P_{2}= pressure of second bulb

P_{3}= pressure of third bulb

P_{4}= initial pressure of tube

V_{1}= Volume of first bulb

V_{2}=Volume of second bulb

V_{3}= Volume of third bulb

V_{4}= Initial volume of tube

Put the value into the formula

8.89\times77.0+250\times2.82+21.0\times8.42+0=P_{f}\times45

P_{f}=\dfrac{1566.35}{45}

P_{f}=34.80\ atm

Hence, The final pressure of the whole system is 34.80 atm.

4 0
3 years ago
Will give brainiest 8th grade physics
Iteru [2.4K]

Answer:

B

Explanation:

Hope this helped!

7 0
3 years ago
A metal ring 4.00 cm in diameter is placed between the north and south poles of large magnets with the plane of its area perpend
liq [111]

Answer:

a) 0.21N/C

b) counterclockwise

Explanation:

a) to find the magnitude of the electric field you can use the following formula:

\int Eds=-\frac{\Delta \Phi_B}{\Delta t}=-\frac{\Delta AB}{\Delta t}

A: area of the ring = pi*r^2

E: electric field

Ф_B: magnetic flux

In the line integral you can assume E as constant. Furthermore, you calculate the change in the magnetic flux by taking into account that the time interval is 1.12/0.21=5.33s. By replacing in the formula you obtain:

\frac{\Delta \Phi_B}{\Delta t}=\frac{A(B_f-B_i)}{5.33s}=\frac{\pi(0.04m)^2(1.12T)}{5.33}=1.056*10^{-3}W/s

E\int ds=E(2\pi r)=1.056*10^{-3}W/s\\\\E=\frac{1.056*10^{-3}W/s}{\pi(0.04m)^2}=0.21\frac{N}{C}

the magnitude if the induced electric field is 0.21N/C

b) By the Lenz's law you can conclude that the current has a direction in a counterclockwise

6 0
3 years ago
The doppler effect is used to determine?
Korolek [52]
Uhh it is used to detirmine heat

7 0
3 years ago
Read 2 more answers
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