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lora16 [44]
3 years ago
13

How much time does it take for a spinning baseball with an angular speed of 38 rad/s to rotate through 15 degrees

Physics
1 answer:
Nadusha1986 [10]3 years ago
3 0

Answer:

the time of motion of the ball is 6.89 ms.

Explanation:

Given;

angular speed, ω = 38 rad/s

angular distance, θ = 15 degrees

Angular distance in radian;

\theta = 15^0 \times\frac{2\pi \ rad}{360^0} = 0.2618 \ rad

Time of motion is calculated as;

time = \frac{angular \ distance}{angular \ speed} \\\\t= \frac{\theta}{\omega} = \frac{0.2618 \ rad}{38 \ rad/s} \\\\t = 6.89 \ \times 10^{-3} \ s\\\\t = 6.89 \ ms

Therefore, the time of motion of the ball is 6.89 ms.

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Answer: 8 years

Explanation:

According to Kepler’s Third Law of Planetary motion <em>“The square of the orbital period of a planet is proportional to the cube of the semi-major axis (size) of its orbit”:</em>

<em />

T^{2}\propto a^{3} (1)

In other words: this law states a relation between the orbital period T of a body (moon, planet, satellite, comet, asteroid) orbiting a greater body in space (the Sun, for example) with the size a of its orbit.  

However, if T is measured in years (Earth years), and a is measured in astronomical units (equivalent to the distance between the Sun and the Earth: 1AU=1.5(10)^{8}km), equation (1) becomes:

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Knowing a=4 AU and isolating T from (2):

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What is the The most appropriate SI unit for measuring the length of an automobile
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