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sdas [7]
3 years ago
6

Add. Write your answer in simplest form. 3/8 + 2/5

Mathematics
1 answer:
Vitek1552 [10]3 years ago
5 0
\frac{3}{8}  +   \frac{2}{5}  =   \frac{(3)(5)}{(8)(5)}   +     \frac{(2)(8)}{(5)(8)}
                                =  \frac{15}{40}   +     \frac{16}{40}
                                =  \frac{31}{40}
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Help pls 20 pts math
Sindrei [870]

Answer:

point a

Step-by-step explanation:

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Help please due in a hour
beks73 [17]

Answer:

The answer is equal to 3/10

Step-by-step explanation:

The values are not very clear

If it's the product of 3/3 and 3/10

Then 3/3 x 3/10

= 9/30

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Round the decimal equivalent of 856 1/6 to the nearest hundredth. What number is in the hundredth place PLEASE HELP
Vika [28.1K]

Answer:

The answer is 856.17.

Step-by-step explanation:

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7 0
3 years ago
(Based on Q1 ~ Q3) According to the Bureau of the Census, 18.1% of the U.S. population lives in the Northeast, 21.9% inn the Mid
vekshin1

Answer:

We can therefore conclude that the geographical distribution of hotline callers could be the same as the U.S population distribution.

Step-by-step explanation:

The null Hypothesis: Geographical distribution of hotline callers could be the same as the U.S. population distribution

Alternative hypothesis: Geographical distribution of hotline callers could not be the same as the U.S. population distribution

The populations considered are the Midwest, South, Northeast, and west.

The number of categories, k = 4

Number of recent calls = 200

Let the number of estimated parameters that must be estimated, m = 0

The degree of freedom is given by the formula:

df = k - 1-m

df = 4 -1 - 0 = 3

Let the significance level be, α = 5% = 0.05

For  α = 0.05, and df = 3,

from the chi square distribution table, the critical value = 7.815

<u>Observed and expected frequencies of calls for each of the region:</u>

<u>Northeast</u>

Observed frequency = 39

It contains 18.1% of the US Population

The probability = 0.181

Expected frequency of call = 0.181 * 200 = 36.2

<u>Midwest</u>

Observed frequency = 55

It contains 21.9% of the US Population

The probability = 0.219

Expected frequency of call = 0.219 * 200 =43.8

<u>South</u>

Observed frequency = 60

It contains 36.7% of the US Population

The probability = 0.367

Expected frequency of call = 0.367 * 200 = 73.4

<u>West</u>

Observed frequency = 46

It contains 23.3% of the US Population

The probability = 0.233

Expected frequency of call = 0.233 * 200 = 46

x^{2} = \sum \frac{(O_{i} - E_{i})  ^{2} }{E_{i} } ,   i = 1, 2,.........k

Where O_{i} = observed frequency

E_{i} = Expected frequency

Calculate the test statistic value, x²

x^{2} = \frac{(39 - 36.2)^{2} }{36.2} + \frac{(55 - 43.8)^{2} }{43.8} + \frac{(60 - 73.4)^{2} }{73.4} + \frac{(46 - 46.6)^{2} }{46.6}

x^{2} = 5.535

Since the test statistic value, x²= 5.535 is less than the critical value = 7.815, the null hypothesis will not be rejected, i.e. it will be accepted. We can therefore conclude that the geographical distribution of hotline callers could be the same as the U.S population distribution.  

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3 years ago
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Sidana [21]

Answer:

its 7 apples

Step-by-step explanation:

Brainliest pls

6 0
3 years ago
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