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3 years ago

Can someone please help me with this algebra

Mathematics

2 answers:

Aliun [14]3 years ago

4 0

Answer:

C. p(t) = 6500(0.88^x)

Step-by-step explanation:

This is the function for simple interest rate.

zhannawk [14.2K]3 years ago

3 0

Answer: A

Step-by-step explanation:

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Logan wants to move to a new city. He gathered graphs of temperatures for two different cities. Which statements about the data

Bad White [126]

Answer:

The correct options are;

Therefore, City A is likely to have temperatures that remain fairly constant all year round because it has a compact interquartile range compared to that of City B

City B is likely to have more extreme temperatures with colder days in the winter and hotter days in the summer because the range is greater than that of A

Step-by-step explanation:

Here we have for City A

Maximum - Minimum = 10

Interquartile range =3

City B

Maximum - Minimum = 18.5

Interquartile range =9.5

Therefore, City A is likely to have temperatures that remain fairly constant all year round because it has a compact interquartile range compared to that of City B

City B is likely to have more extreme temperatures with colder days in the winter and hotter days in the summer because the range is greater than that of A.

7 0

3 years ago

Read 2 more answers

Is the line through points P(–3, –2) and Q(2, 3) perpendicular to the line through points R(10, –1) and S(15, –6)? Explain.

Alexus [3.1K]

Answer:

B. Yes. Their slopes have product -1.

Step-by-step explanation:

Given:

Line passing through P(-3, -2) and Q(2, 3)

Line passing through R(10, -1) and S(15, -6)

Required:

To determine if both lines are perpendicular.

SOLUTION:

Two lines are considered perpendicular if the product of their slopes equal -1.

To determine if both lines given in the question are perpendicular, first, calculate their slope using: $m = \frac{y_2 - y_1}{x_2 - x_1}$

Slope of line passing through P(-3, -2) and Q(2, 3):

Let,

$P(-3, -2) = (x_1, y_1)$

$Q(2, 3) = (x_2, y_2)$

$m = \frac{3 -(-2)}{2 -(-3)}$

$m = \frac{5}{5} = 1$

Slope of line passing through R(10, -1) and S(15, -6):

Let,

$R(10, -1) = (x_1, y_1)$

$S(15, -6) = (x_2, y_2)$

$m = \frac{-6 -(-1)}{15 - 10}$

$m = \frac{-5}{5} = -1$

The product of their slopes = 1 × -1 = -1

Therefore, the lines are perpendicular.

The answer is: B. "Yes. Their slopes have product -1."

5 0

4 years ago

Can someone help please?

Pie

The first one because it’s the greater number

7 0

3 years ago

To find the length of a line segment given endpoints is to use ______

ivann1987 [24]

Answer:

To calculate the distance d of a line segment with endpoints (x1, y1) and (x2, y2) use the formula d (x2 x1)2 (y2 y1)2. * i didnt know what to put so i put this*

8 0

3 years ago

Help please asap!!! working too please not just the answers!!

omeli [17]

Answer:

Area = 4600m

explanation: I worked it out in the image attached if that helps let me know if you need a more in depth explanation step by step

8 0

3 years ago

Read 2 more answers