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kupik [55]
3 years ago
15

The vertex of this parabola is at (-5, -2). When the x-value is -4, they-value is 2. What is the coefficient of the squared expr

ession in the parabola's equation?
Mathematics
1 answer:
asambeis [7]3 years ago
6 0
K, so
vertex i (-5,-2)
neat

vertex form
y=a(x-h)²+k
vertex is (h,k)
a is the coefieint of the squred term in the parbola's equestion
so
given vertex of (-5,-2)

y=a(x-(-5))²+(-2)
y=a(x+5)²-2
a point si (-4,2)
sub that point
2=a(-4+5)²-2
2=a(1)²-2
2=a-2
add 2
4=a

the value of the coefieint of the squred expression part is 4
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Express 2x+1/(x-2)(x²+1) as a partial fraction.

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(2x+1) / ( (x-2)(x^2+1) )

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(2x+1) / ( (x-2)(x^2+1) ) = ( (A+B)x^2+(C-2B)x+A-2C ) / ( (x-2)(B/(x^2+1) )

Match numerators

2x+1 = (A+B)x^2+(C-2B)x+A-2C

Match coefficients,

A+B = 0 ..................(1)

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Solve for A, B and C

Substitute A from (1) in (3)

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B = -2C-1  ....................(4)

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