The vertex of this parabola is at (-5, -2). When the x-value is -4, they-value is 2. What is the coefficient of the squared expr ession in the parabola's equation?
1 answer:
K, so vertex i (-5,-2) neat vertex form y=a(x-h)²+k vertex is (h,k) a is the coefieint of the squred term in the parbola's equestion so given vertex of (-5,-2) y=a(x-(-5))²+(-2) y=a(x+5)²-2 a point si (-4,2) sub that point 2=a(-4+5)²-2 2=a(1)²-2 2=a-2 add 2 4=a the value of the coefieint of the squred expression part is 4
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x = 50
m∠D = 150°
m∠F = 30°
Step-by-step explanation:
supplementary angles are two angles whose sum is 180° ∠D + ∠F = 180°
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