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3 years ago

Which is an estimate of square root of 15 to one decimal place?

Mathematics

2 answers:

Wewaii [24]3 years ago

8 0

3.9 is the estimated square root of 15 to one decimal place

Lena [83]3 years ago

3 0

3.9 will be the estimate

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What is the surface area of a rectangular prism that has i height of 2 length of 5 and width of 13

BaLLatris [955]

Answer:

A=202

Step-by-step explanation:

A=2(wl+hl+hw)

2·(13·5+2·5+2·13)=202

7 0

3 years ago

The symphonic choir and the jazz choir are recording songs for an album. The album can be no more than 72

Brut [27]

Answer:

The maximum number of songs that the symphonic choir can record is 14

Step-by-step explanation:

Let

x ----> the number of songs of the symphonic choir

we know that

The number of songs of the jazz choir multiplied by its average time per song plus the the number of songs of the symphonic choir multiplied by its average time per song, must be less than or equal to 72 minutes

The inequality that represent this situation is

$3(7)+3.5(x)\leq 72$

solve for x

$21+3.5x\leq 72$

subtract 21 both sides

$3.5x\leq 51$

divide by 3.6 both sides

$x\leq 14.6\ songs$

therefore

The maximum number of songs that the symphonic choir can record is 14

3 0

3 years ago

Find the value of y in the solution to the system of equations shown. 3y=18x+6 y=2x+14

ololo11 [35]

Answer:

y=14

Step-by-step explanation:

because I solved it and got 14 ......

5 0

2 years ago

Use implicit differentiation to find an equation of the tangent line to the curve at the given point. x2/3 + y2/3 = 4 (−3 3 , 1)

vovikov84 [41]

Answer with Step-by-step explanation:

We are given that an equation of curve

$x^{\frac{2}{3}}+y^{\frac{2}{3}}=4$

We have to find the equation of tangent line to the given curve at point $(-3\sqrt3,1)$

By using implicit differentiation, differentiate w.r.t x

$\frac{2}{3}x^{-\frac{1}{3}}+\frac{2}{3}y^{-\frac{1}{3}}\frac{dy}{dx}=0$

Using formula : $\frac{dx^n}{dx}=nx^{n-1}$

$\frac{2}{3}y^{-\frac{1}{3}}\frac{dy}{dx}=-\frac{2}{3}x^{-\frac{1}{3}}$

$\frac{dy}{dx}=\frac{-\frac{2}{3}x^{-\frac{1}{3}}}{\frac{2}{3}y^{-\frac{1}{3}}}$

$\frac{dy}{dx}=-\frac{x^{-\frac{1}{3}}}{y^{-\frac{1}{3}}}$

Substitute the value x= $-3\sqrt3,y=1$

Then, we get

$\frac{dy}{dx}=-\frac{(-3\sqrt3)^{-\frac{1}{3}}}{1}$

$\frac{dy}{dx}=-(-3^{\frac{3}{2}})^{-\frac{1}{3}}=-\frac{1}{-(3)^{\frac{3}{2}\times \frac{1}{3}}}=\frac{1}{\sqrt3}$

Slope of tangent=m= $\frac{1}{\sqrt3}$

Equation of tangent line with slope m and passing through the point $(x_1,y_1)$ is given by

$y-y_1=m(x-x_1)$

Substitute the values then we get

The equation of tangent line is given by

$y-1=\frac{1}{\sqrt3}(x+3\sqrt3)$

$y-1=\frac{x}{\sqrt3}+3$

$y=\frac{x}{\sqrt3}+3+1$

$y=\frac{x}{\sqrt3}+4$

This is required equation of tangent line to the given curve at given point.

8 0

3 years ago

he graph of f(x) = |x| is stretched by a factor of 0.3 and translated down 4 units. Which statement about the domain and range o

vampirchik [111]

Answer:

Out of the four, the only statement true about the parent and the transformed function is:

"The domain of the transformed function and the parent function are all real numbers."

Step-by-step explanation:

Parent function:

f(x) = |x|

Applying transformations:

1. Stretched by a factor of 0.3:

f(x) = 3|x|

2. Translated down 4 units:

f(x) = 3|x| - 4

Transformed function:

f(x) = 3|x| - 4

We can see that:

Range of the parent function = All real numbers greater than or equal to 0.

Range of the transformed function = All real numbers greater than or equal to -4.

Domain of the parent and the transformed function is same and equal to all real numbers.

Hence, the first three statements are wrong and the fourth one is true.

6 0

3 years ago

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