If it's x²y³ then we know it's the second term of the expansion, that known we can use the combination
C(5, 2) = 5!/(2!.3!) = 10
Then if we had something like
(a + b)^5 our second term would be 10a²b³ but as we can see it's "a²"
And in our case we have 2x as a
So we must do 2² too
2² = 4
10 . 4 = 40
Then our second term of the expansion would be
40x²y³
Question asked:Jacob and Sarah are saving money to go on a trip. They need at least $1975 in order to go. Jacob mows lawns and Sarah walks dogs to raise money. Jacob charges $25 each time he mows a lawn and Sarah charges $15 each time she walks a dog. The number of dog walks that Sarah has scheduled is no more than four times the number of lawns Jacob has scheduled to mow. Sarah will walk at least 50 dogs.Write a set of constraints to model the problem, with x representing the number of lawns mowed and y representing the number of dogs walked.
My answer:
They need at least $1975. Jacob charges $25 each time he mows a lawn and Sarah charges $15 each time she walks a dog.
25x + 15y ≥ 1975
The number of dog walks that Sarah has scheduled is no more than four times the number of lawns Jacob has scheduled to mow.
y ≤ 4x
Sarah will walk at least 50 dogs.
y ≥ 50
Answer:
x
Step-by-step explanation:
the value of x is the input and value of y is the output
