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skad [1K]
4 years ago
5

Guys help with 16 abc A lot of points please hellllp

Mathematics
1 answer:
luda_lava [24]4 years ago
4 0
A.
well, to find the perimeter of a rectangle, it is 2(length+width)
using this, the perimeter of the tennis court is 2(2x+6+x)=2(3x+6)=6x+12
the perimeter of the basketball court is 2(3x-14+1/2x+32)=2(2 1/2x+18)= 5x+36
B. 
the difference is subtraction, so it'd be 6x-12-(5x+36)
C.
width is 2x+6
2x+6=36
2x=30
x=15
tennis: 15 by 36
basketball: 3*15-14= 31
1/2*15+32= 39.5
31 by 39.5
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Let f(x)=2x+2. Solve f^-1(x) when x=4
Gre4nikov [31]
F⁻¹(x) stands for the invers of function f(x). The inverse of f(x) is equal to x. We need to solve for x.

solve for x
f(x) = 2x + 2
2x + 2 = f(x)
2x = f(x) - 2
  x = \dfrac{f(x)-2}{2}
f⁻¹(x) = \dfrac{x-2}{2}

Determine the value of f⁻¹(x) when x = 4
f⁻¹(x) = \dfrac{x-2}{2}
f⁻¹(4) = \dfrac{4-2}{2}
f⁻¹(4) = \dfrac{2}{2}
f⁻¹(4) = 1
When x = 4, the value of f⁻¹(x) is equal to 1
4 0
3 years ago
I will give a brainlist if someone could answer this problem with a explanation:)
egoroff_w [7]

Answer:

Step-by-step explanation:

The two base angles in each triangle are equal. (The triangle is isoceles and the property used is angles opposite equal sides are equal).

Now the tricky part. The peak angles are also equal. That's because both peak angles are made equal by Peak angle + 2*base angle = 180

Peak angle = 180 - 2*base angle

Therefore the triangles are congruent by SAS.  

I suppose you could get them equal by taking one of the base angles (all 4 are equal to each other) and the peak angles and claim equality by ASA, but it seems a little bit tortuous to me.

5 0
3 years ago
What is the area of triangle ABC? Round to the nearest hundredth of a square unit. 17. 75 square units 81. 33 square units 372.
jolli1 [7]

The area of the triangle ABC is 81. 33 square units.

We have to determine

What is the area of triangle ABC?

<h3>What is the formula for the area of a triangle?</h3>

The area of the triangle is determined by;

\rm Area \ of \ triangle = s\sqrt{s(s-a)(s-b)(s-c)}

Where the value of s is = a + b + c= 12 + 14 + 16 = 42

Substitute all the values in the formula;

\rm Area \ of \ triangle = \sqrt{s(s-a)(s-b)(s-c)}\\\\\rm Area \ of \ triangle = \sqrt{21(21-12)(21-14)(21-16)}\\\\\rm Area \ of \ triangle = \sqrt{(21 \times 9 \times 7 \times 5)}\\\\Area \ of \ triangle =\sqrt{6,615}\\\\Area \ of \ triangle = 81.33

Hence, the area of the triangle ABC is 81. 33 square units.

To know more about the Area of the triangle click the link given below.

brainly.com/question/9299277

5 0
2 years ago
A book sold 34,200 copies in its first month of release. Suppose this represents 8.8% of the number of copies sold to date. How
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388,636.36 copies have been sold
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3 years ago
Finf the exact value of sin A and cos A where a = 9 and b = 10 and &lt;c is a right angle
Katyanochek1 [597]
To solve for the longest side, the hypotenuse, you have to use the pythagorean theorem. It will be 10^2 + 9^2 = c^2. 100 + 81 =c^2. 
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to find cos of A do adjacent/hypotenuse which gives you 10/sqrt(181)

8 0
3 years ago
Read 2 more answers
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