Find the interquartile range of the data displayed in the box plot shown.

Mathematics

2 answers:

Tanya [424]2 years ago

7 0

The interquartile range is 6.

all you have to do is find the range of where that rectangle starts and ends, so 9-3=6. hope that helps :)

kicyunya [14]2 years ago

5 0

6.

The upper quartile is at 9. The lower quartile is at 3. The inner quartile range is the difference of those 2 numbers. 9-3=6

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For number 6, evaluate the definite integral.

maks197457 [2]

$\bf \displaystyle \int\limits_{0}^{28}\ \cfrac{1}{\sqrt[3]{(8+2x)^2}}\cdot dx\impliedby \textit{now, let's do some substitution}\\\\
-------------------------------\\\\
u=8+2x\implies \cfrac{du}{dx}=2\implies \cfrac{du}{2}=dx\\\\
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$\bf \displaystyle \int\limits_{0}^{28}\ \cfrac{1}{\sqrt[3]{u^2}}\cdot \cfrac{du}{2}\implies \cfrac{1}{2}\int\limits_{0}^{28}\ u^{-\frac{2}{3}}\cdot du\impliedby 
\begin{array}{llll}
\textit{now let's change the bounds}\\
\textit{by using } u(x)
\end{array}\\\\
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$\bf \\\\
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3 0

2 years ago

6w + 2(4w - 7) simplified

Gemiola [76]

Answer:

14w -14

Step-by-step explanation:

6w + 2(4w - 7)

Distribute

6w+ 8w -14

Combine like terms

14w -14