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Hatshy [7]
3 years ago
10

I can read a 336-page book in 6 hours. Jayne can read a 144-page book in 3 hours. If I start reading a 5000-page book at noon an

d Jayne starts reading the same book at 10 AM, what time will it be when we are on the same page at the same time?
Mathematics
1 answer:
dimulka [17.4K]3 years ago
8 0

Answer:

12:00 am midnight

Step-by-step explanation:

Given;

I can read a 336-page book in 6 hours.

My rate r1 = 336/6 pages per hour = 56 pages per hour

Jayne can read a 144-page book in 3 hours.

Jayne rate r2 = 144/3 = 48 pages per hour

If I start reading a 5000-page book at noon and Jayne starts reading the same book at 10 AM

Taking 10 am as the reference time.

Let x represent the time from 10 am at which they would both be on the same page.

For me;

Since i started by noon; 2 hours after 10 am

Time t1 = x-2

For Jayne;

She started by 10 am

Time t2 = x

For them to be on the same page they must have read the same number of pages;

Number of pages read = rate × time

r1(t1) = r2(t2)

Substituting the values;

56(x-2) = 48(x)

56x - 112 = 48x

x(56-48) = 112

x = 112/(56-48)

x = 14 hours

Since 10 am is the reference, the time would be;

=10 am + x = 10 am + 14 hours

= 24:00

= 12:00 am midnight

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balandron [24]

Answer:

146

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<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

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  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Algebra I</u>

  • Coordinates (x, y)

<u>Algebra II</u>

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Step-by-step explanation:

<u>Step 1: Define</u>

Point A(2, 125)

Point B(98, 15)

<u>Step 2: Identify</u>

A(2, 125) → x₁ = 2, y₁ = 125

B(98, 15) → x₂ = 98, y₂ = 15

<u>Step 3: Find distance </u><em><u>d</u></em>

  1. Substitute in coordinates [Distance Formula]:                                               \displaystyle d = \sqrt{(98-2)^2+(15-125)^2}
  2. [√Radical] (Parenthesis) Subtract:                                                                   \displaystyle d = \sqrt{(96)^2+(-110)^2}
  3. [√Radical] Evaluate exponents:                                                                       \displaystyle d = \sqrt{9216+12100}
  4. [√Radical] Add:                                                                                                 \displaystyle d = \sqrt{21316}
  5. [√Radical] Evaluate:                                                                                         \displaystyle d = 146
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Is the expression 70 – (4 • 15) a difference of three terms, a product of two terms, or a difference of two terms?
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I'm confused. Help. Find x please.
miss Akunina [59]

Answer:

x = 2 and x = 10

Step-by-step explanation:

(x+3)^2 = (x - 5)^2 + (x + 2)^2

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Hamburgers cost $2.50 and cheeseburgers cost $3.50 at a snack bar. Ben has sold no more than $30 worth of hamburgers and cheeseb
Irina18 [472]

Given 2.50x + 3.50y < 30.

Where x represent the number of hamburgers and y represent the number of cheeseburgers.

Now question is to find the maximum value of hamburgers Ben could have sold when he has sold 4 cheeseburgers.

So, first step is to plug in y=4 in the given inequality. So,

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2.50x<30- 14 Subtracting 14 from each sides.

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\frac{2.50x}{2.50} Dividing each sides by 2.50.

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Now x being number of hamburgers must be an integer , so tha maximum value of x can be 6,

thus x = 6 hamburgers

So, the maximum value of hamburgers Ben could have sold is 6*2.5=$15

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