I will try to solve your system of equations.
3
x
−
4
y
=
2
;
9
x
−
12
y
=
6
Step: Solve
3
x
−
4
y
=
2
for x:
3
x
−
4
y
+
4
y
=
2
+
4
y
(Add 4y to both sides)
3
x
=
4
y
+
2
3
x
3
=
4
y
+
2
3
(Divide both sides by 3)
x
=
4
3
y
+
2
3
Step: Substitute
4
3
y
+
2
3
for
x
in
9
x
−
12
y
=
6
:
9
x
−
12
y
=
6
9
(
4
3
y
+
2
3
)
−
12
y
=
6
6
=
6
(Simplify both sides of the equation)
6
+
−
6
=
6
+
−
6
(Add -6 to both sides)
0
=
0
Answer:
Infinitely many solutions.
Answer:
<u>x²-14x+48</u>
Step-by-step explanation:
Area= Length × Width
Area= x-6 × x-8
Area= (x-6)(x-8)
Area= x²-8x-6x+48
Area= x²-14x+48
Hope this helped you- have a good day bro cya)
Answer:

Step-by-step explanation:
Let
represent the amount of money he initially started with.
After he spent 20% on books, he will have
of his initial money left. We can represent this as
.
Following that, the boy spends 20% of the remainder of his money on food. Similarly, he will have
of the remainder of money he had left after he purchased the books. Therefore, he ends up with
of his money left.
Since we're given that he had $2,000 after all these transactions, we have the following equation:

Divide both sides by 0.64 to isolate and solve for
:

Therefore, the boy had $3,125 to begin with.