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3 years ago

How can you find the area of a polygon that is not for which you know an area formula

Mathematics

1 answer:

kipiarov [429]3 years ago

6 0

Answer:

See below.

Step-by-step explanation:

If it is a regular polygon then you can look up the formula or break it into shapes you do know the formula.

If it is irregular or a composite figure, break it into regular polygons which do have formulas to find the area. Here is an example:

Example:

Find the area of the composite figure by splitting the figure into two shapes - two rectangles.

One rectangle is 2 x 9 = 18.

The other rectangle is 2 x 4 = 8.

Together the area is 18 + 8 = 26.

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Determine if the graph is symmetric about the x-axis, the y-axis, or the origin. r = 5 cos 3θ

Aneli [31]

First of all get a picture of what this looks like. Desmos is a pretty good graphing program, but anything that will do polar coordinates will work.

Here is the graph.

What you can see is that this graph is symmetrical around the x axis.

When you talk about symmetry, you can think of it as taking a mirror and putting it where you think there is symmetry. If you can't tell the difference between the image and the real thing, then you have symmetry.

In this case, the mirror will show symmetry along the x axis and no where else.

4 0

3 years ago

Read 2 more answers

Can I get some help, it is due in 15 minutes and I need help. Thanks, any help appreciated

koban [17]

Well, I'm way past the 15 min mark, but here's how to do the question.

With this, you will need to use the distance formula, $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ , on XY, YZ, and ZX.

XY: $\sqrt{(3-1)^2+(1-6)^2}$

Firstly, solve inside the parentheses: $\sqrt{(2)^2+(-5)^2}$

Next, solve the exponents: $\sqrt{4+25}$

Next, solve the addition, and XY's distance will be √29

(The process is the same with the other 2 sides, so I'll go through them real quickly)

YZ:

$\sqrt{(6-3)^2+(3-1)^2}\\ \sqrt{(3)^2+(2)^2}\\ \sqrt{9+4}\\ \sqrt{13}$

ZX:

$\sqrt{(1-6)^2+(6-3)^2}\\ \sqrt{(-5)^2+(3)^2}\\ \sqrt{25+9}\\ \sqrt{34}$

Now that we got the 3 sides, we can add them up: $\sqrt{29}+\sqrt{13} +\sqrt{34} =14.8$

In short, your answer is 14.8, or the second option.

8 0

3 years ago

Consider the sets below. u = {x | x is a real number} a = {x | x is an odd integer} r = {x | x = 3, 7, 11, 27} is r ⊂ a?

-BARSIC- [3]

The correct option is (B) yes because all the elements of set R are in set A.

<h3>What is an element?</h3>

In mathematics, an element (or member) of a set is any of the distinct things that belong to that set.

Given sets:

U = {x | x is a real number}
A = {x | x is an odd integer}
R = {x | x = 3, 7, 11, 27}

So,

A = 1, 3, 5, 7, 9, 11... are the elements of set A.
R ⊂ A can be understood as R being a subset of A, i.e. all of R's elements can be found in A.
Because all of the elements of R are odd integers and can be found in A, R ⊂ A is TRUE.

Therefore, the correct option is (B) yes because all the elements of set R are in set A.

Know more about sets here:

brainly.com/question/2166579

#SPJ4

The complete question is given below:
Consider the sets below. U = {x | x is a real number} A = {x | x is an odd integer} R = {x | x = 3, 7, 11, 27} Is R ⊂ A?

(A) yes, because all the elements of set A are in set R

(B) yes, because all the elements of set R are in set A

(D) no, because each element in set R is not represented in set A

8 0

1 year ago

The area of a rectangular flower bed is 24 square feet. The perimeter of the same flower bed is 22 feet. What are the dimensions

Vesna [10]

Answer:

3 ft by 8 ft

Step-by-step explanation:

We were given the area as 24 square feet which means that

L×w= 24....eqn(1)

We were given the perimeter as 22 square feet which means that

22= 2(L +w).......eqn(2)

If we divide both cause by 2 in eqn(2) we have

11= L+ w .....eqn(3)

W= 11-L.........eqn(4)

Substitute eqn(4 into eqn(1)

L× (11-L)=24

-L^2 +11L-24=0

If we factorize

(L-8)(L-3)

L=3 or 8

From eqn4)

W=11-L

At L=3

W=11-3=8

Hence, the dimension is 3 ft by 8 ft

4 0

3 years ago

Jaden learns to perform 2 vocal pieces during each week of lessons . How many weeks of lessons will Jaden need before he will be

storchak [24]

Answer:

12 weeks

Step-by-step explanation:

To solve this, all you need to do is divided 24 pieces by the two he learns per week. You'll then find it will take him 12 weeks

6 0

3 years ago